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A BAG CONTAINS 12 DISCS. THERE ARE 8 BLUE AND 4 RED DISCS.A DISC IS PICKED OUT AT RANDOM AND NOT REPLACED. A SECOND DISC IS THEN PICKED OUT AT RANDOM AND NOT REPLACED.1) DRAW A TREE DIAGRAM.2)EXPRESS EACH OF UR ANSWER AS A FRACTION IN ITS LOWEST TERMS ,CALCULATE THE PROBABILITY THAT : a) BOTH DISCS ARE RED b) AT LEAST ONE DISC IS BLUE c) A THIRD DISC IS PICKED OUT AT RANDOM.CALCULATE THE PROBABILITY THAT ALL THREE DISCS ARE RED. ...... GUYS NOTE THAT..I HAVE SOLVED ALL THE PARTS BUT PART (c) IS NOT CLEAR TO ME...SO PLZ...IF ANY ONE TRIES TO SOLVE THIS QUESTION JUST TELL ME THE ANSWER OF (c).:)

Mathematics
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|dw:1358862778742:dw|
Your tree diagram looks corect
P(RRR) =12/132 * 2/10

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got it?
OK THANKS FRND..I GOT IT
welcome
P(RRR) = 4/12 *3/11 *2/10 =(4*3*2)/(12*11*10) = 1/55
OK THANKS AGAIN

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