anonymous
  • anonymous
Please Help!!!Assume that the atmosphere is isothermal with T = 15 degrees Celsius. What is the value of the scale height (in km)? At approximately what height above sea level (z0 = 0 m) does 75% of the mass of the atmosphere lie above and the remaining 25% lie below?
Engineering
katieb
  • katieb
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anonymous
  • anonymous
I first cnverted 15 degrees Celsium to 288.15 Kelvin and since it said isothermal i thought it was safe to assume that |dw:1358874275693:dw|
anonymous
  • anonymous
then i used the equation |dw:1358874307153:dw|
anonymous
  • anonymous
i ended up getting( (287 J/kgK)*(288.15K))/9.81 m/s^2

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anonymous
  • anonymous
=8430.0764 but i dont know itf this part ic correct for the first part bc im not sure if its in km Also i have no idea on hat to do for the second part

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