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Can somebody please check my work? - Giving medals. (; (Picture below.)

Mathematics
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I think you're a bit confused. The area of a right triangle is 1/2 base * height which you already know. The problem only gives you the hypotenuse and the base. You need to calculate the height before calculating the area. You can use the Pythagorean theorem to calculate the height pretty easily.
Both of them are wrong?

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Yes, both are wrong. The height in the first one does come out to be 7.14 though...but you have then calculate the area.
Alright. So for the first one, A=1/2(7.14) times what? 15 or 9?
For the first one: \[a^2+b^2=c^2\]\[7^2+b^2=10^2\]\[b^2=51\]\[b=7.14\] \[A=\frac{1}{2}(7)(7.14)=?\]The second one is answered the same way
Where do you get 7?
The first problem states that the leg (base) length is 7.
Nvm, I got confused. Sorry.
So for the first one: A=599.76
Did you put the above in a calculator? That's not even close :/
You should get an area of ~25
Oh wait! I put it in wrong, I got Area=24.99
That's correct :) Now just do the second one the same way
For the second one, I used the Pythagorean theorem and I got B=13.6015?
Btw thank for all the help and patience! @Shane_B
Neverming..windows calculator mistake. Yep, that's correct.
Okay so now, the answer should be A=142.8158?
The base of the triangle is 16 and you calculated the height to be 13.6015. So the area should be:\[A=\frac{1}{2}bh=\frac{1}{2}(16)(13.6015)=108.812\]
Oh! That's what I did wrong. I used 21 instead of 16. Thank you so much.
np :)

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