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Can you simplify the first radical by finding the perfect square that fits in it?

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11s isn't an option ):
@HorseCrazyGirlForever Try not to just post the answer.. try to explain how ya got there
i believe so
So what perfect square fits into 18?
\[\sqrt{18x}+\sqrt{2x}\] \[=\sqrt{9\times2x}+\sqrt{2x}\] \[=\sqrt{9}\times\sqrt{2x}+\sqrt{2x}\] \[=\sqrt{3^2}\times\sqrt{2x}+\sqrt{2x}\] \[=\]
Geez I don't know if that is correct... :(
Could I get some help with my question when you guys are done here? I really need to get it done....
UncleRhaukus, the final answer isn't showing ):
You're supposed to figure it out!
I dont think he wanted it to show, i think he wanted you to do it
i need to get this overwith, so if anyone can just give me the answer real quick, i'll give them their medal.
Oh, come on, it's easy! What is 3*3? and what number * itself gives you 9?
\[=\sqrt{3^2}\times\sqrt{2x}+\sqrt{2x}\] simplify this bit \(\sqrt{3^2}\) then combine the like terms

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