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meganemma1995

  • 3 years ago

add! medal for the CORRECT answer!

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  1. meganemma1995
    • 3 years ago
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  2. HorseCrazyGirlForever
    • 3 years ago
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    11x?

  3. zaynahf
    • 3 years ago
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    Can you simplify the first radical by finding the perfect square that fits in it?

  4. meganemma1995
    • 3 years ago
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    11s isn't an option ):

  5. zaynahf
    • 3 years ago
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    @HorseCrazyGirlForever Try not to just post the answer.. try to explain how ya got there

  6. meganemma1995
    • 3 years ago
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    i believe so

  7. zaynahf
    • 3 years ago
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    So what perfect square fits into 18?

  8. UnkleRhaukus
    • 3 years ago
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    \[\sqrt{18x}+\sqrt{2x}\] \[=\sqrt{9\times2x}+\sqrt{2x}\] \[=\sqrt{9}\times\sqrt{2x}+\sqrt{2x}\] \[=\sqrt{3^2}\times\sqrt{2x}+\sqrt{2x}\] \[=\]

  9. HorseCrazyGirlForever
    • 3 years ago
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    Geez I don't know if that is correct... :(

  10. HorseCrazyGirlForever
    • 3 years ago
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    Could I get some help with my question when you guys are done here? I really need to get it done....

  11. meganemma1995
    • 3 years ago
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    UncleRhaukus, the final answer isn't showing ):

  12. meganemma1995
    • 3 years ago
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    @UncleRhaukus

  13. whpalmer4
    • 3 years ago
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    You're supposed to figure it out!

  14. zaynahf
    • 3 years ago
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    I dont think he wanted it to show, i think he wanted you to do it

  15. meganemma1995
    • 3 years ago
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    ughhhhhh

  16. meganemma1995
    • 3 years ago
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    i need to get this overwith, so if anyone can just give me the answer real quick, i'll give them their medal.

  17. whpalmer4
    • 3 years ago
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    Oh, come on, it's easy! What is 3*3? and what number * itself gives you 9?

  18. UnkleRhaukus
    • 3 years ago
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    \[=\sqrt{3^2}\times\sqrt{2x}+\sqrt{2x}\] simplify this bit \(\sqrt{3^2}\) then combine the like terms

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