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 one year ago

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you have formula for this problem. that is [(sinx)' (1+ cosx)  (1+cosx)' sinx]/ (1 + cosx)^2 Now, i separate into 2 parts: numerator and denominator. numerator first: (sinx)' = cosx; (1 + cos x)' = sinx. so, the numerator = cosx (1 + cosx)  (sinx)(sinx)= cosx + (cosx)^2 + (sinx)^2 and we have (cosx)^2 + (sinx)^2 =1. so, the numerator = cosx +1 = 1 + cosx. combine with denominator, we have the solution is 1/ 1+ cosx. hope this help
 one year ago
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