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yea, ive tried google
@whpalmer4 can you help?
@jim_thompson5910 can you help me with these couple of questions about geometry proofs?
how far did you get on #2
um i think i finished that one, not sure let me check
ok post what you got
im not so sure how to do it?
or just write it out here
like what do you mean?
# 2 im not sure what to do
what is the first step i need to do @jim_thompson5910 ?
well start with what you are given
so would it be BCD=EDC BCD=ECD
both are given?
good, start off saying those two sets of angles are congruent because that's given
so then it would look like this? BCD=EDC|GIVEN BCD=ECD|GIVEN and then now what?
what segments can you say for sure are congruent
uuhmm not so sure.
i would have to say that BCD and BED are congruent right?
what segment is between angles BCD and EDC
is it just one segment?
yes do you see it?
segment, not angle
that's a point, not a segment
whats a segment?
there's the figure |dw:1358891844771:dw|
what I'm talking about is this segment (in black) |dw:1358891880746:dw|
ohhh C and D sorry lol
you mean segment CD right?
yes hhaha lol
that's the shared side between the two triangles that overlap
CD = CD by the reflexive property
then you can say those two overlapping triangles are congruent by the ASA property
okay, so what would our whole overall problem look like? ill do it, and you see if it looks correct
BCD=EDC|GIVEN BCD=ECD|GIVEN so CD=CD by the reflexive property the two overlapping triangles are congruent by the ASA property would this be what it look like?
you'll have to be specific by actually naming the triangles
BCD=EDC|GIVEN BCD=ECD|GIVEN so CD=CD by the reflexive property BCD and EDC are congruent by the ASA property how about this?^^
you nailed it
awesome! okay how about the next one now:)
oh you might want to say triangles BCD and EDC are congruent by the ASA property so you don't confuse them with angles
ok how do we get started on the next one
we have to start with what we are given.
exactly, so go ahead and state that
im not sure how that to start this one because Ive never done one with a midpoint in it, but ill try real quik
well you start off by stating that D is the midpoint of AC (given) then you use the definition of midpoint to say that AD = CD
BDC=BDA|GIVEN BCD=BAD|GIVEN RIGHT?
where does it say that BCD=BAD is given?
actually no lol
but the first one is given
so add that on
AD = CD not because it's given, but by the definition of midpoint
A midpoint cuts a line segment into two equal halves
so then how do i find my other given?
You're done with you're givens
oh so theirs only one given then
Now you need one more side or one more angle, here is a visual hint: |dw:1358892974213:dw|
There are 2 givens, but you've used them up already
so then if we have BDC=BDA|GIVEN I would have to look at the other angle i have on the picture to get my other given?
see those segments i highlighted?
they are congruent, do you see why?
yes, because they have equal sides right?
they are congruent because they are the same segment BD |dw:1358893344746:dw|
so you'll have to say BD = BD and give a reason why that's true
so I would say BD=BD are reflective property ?
okay and then I say why my triangles are congruent?
yes and which property will you use
this may help |dw:1358893552844:dw|
so then it would look like this: BDC=BDA|GIVEN So BD=BD by the reflective property Triangles BDC and BDA are congruent by the ASA property is this right?
you're missing something
AD = DC but why is that?
and remember you have 2 given statements
because its the midpoint, where would i place it?
and it's not the ASA property
would it be the SAS property?
yes that's correct
BDC=BDA|GIVEN AD = DC|GIVEN So BD=BD by the reflective property Triangles BDC and BDA are congruent by the SAS property
no AD = DC is not given
go back and look at the doc and you'll see it's not given
okay, so then what would our next given be and is SAS correct for the property?
yes it's SAS
look back at the doc, and simply restate what they give
all i see is Dis the midpoint of side AC, and then BDC=BDA
there you go
just restate those and say given
that will allow you say that AD = DC because of the definition of midpoint
so how would it look ?
like you had it, just add those lines in
okay, where would I put that at when i put my answer in?
so would it look like this: BDC=BDA|GIVEN side AD =side DC|GIVEN So BD=BD by the reflective property Triangles BDC and BDA are congruent by the SAS property
put those givens at the top, then put AD = DC | definition of midpoint right after that
AD = DC | definition of midpoint BDC=BDA|GIVEN So BD=BD by the reflective property Triangles BDC and BDA are congruent by the SAS property
you forgot AD = DC | definition of midpoint again
BDC=BDA|GIVEN AD=DC|GIVEN AD = DC | definition of midpoint So BD=BD by the reflective property Triangles BDC and BDA are congruent by the SAS property
OK last one!:)
ok show me what you got for this one
I got: AB=CD|GIVEN BF=ED|GIVEN is this right?
AB || CD, not AB = CD
also, angle B = angle D | given
so then it would look like this AB||CD|GIVEN angle B=angle D|given
along with BF=ED|GIVEN
you have 3 given statements
oh how would i order them?
in any order, all 3 are given and don't depend on one another
AB||CD|GIVEN angle B=angle D|given BF=ED|GIVEN now what?
because AB || CD, we can say that angle BAF = angle DCE because they are alternate interior angles
so essentially angle BAF = angle DCE | alternate interior angles what's next?
you have 2 angles, and a side, which congruence property can you use?
BAF=angle DCE|alternate interior angles angle B=angle D|given BF=ED|GIVEN just to clear it up is this right^^ if its not can you correct it?
you put the givens first though the "given" statements always come first
since you always start with what you are given
and you build from there
BF=ED|GIVEN angle B=angle D|given BAF=angle DCE|alternate interior angles
you forgot the line AB||CD | given
where do i put that that at
above the "alternate interior angles" line
BF=ED|GIVEN angle B=angle D|given AB||CD | given BAF=angle DCE|alternate interior angles
okay now what:)
you have 2 angles, and a side, which congruence property can you use?
ASA OR AAS
you would use AAS because the two angles are adjacent and the last side is not between them
Ok, so then would i say anything about reflective property?
no you can't use the reflexive property for this one
so it looks like this: BF=ED|GIVEN angle B=angle D|given AB||CD | given BAF=angle DCE|alternate interior angles triangle BF and ED are congruent by the AAS property
last line is more like triangle ABF and triangle CDE are congruent by the AAS property
okay, but otherwise it looks good?
yes it looks great
thanks so much jim! you tha best:))