katlin95
can someone help me with these 3 proofs, I have attached the file.. it has to get done by today! and i really appreciate it:) medals rewarded!
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katlin95
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katlin95
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@roberman228
katlin95
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okay:)
katlin95
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yea, ive tried google
katlin95
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@whpalmer4 can you help?
katlin95
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@jim_thompson5910 can you help me with these couple of questions about geometry proofs?
jim_thompson5910
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how far did you get on #2
katlin95
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um i think i finished that one, not sure let me check
jim_thompson5910
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ok post what you got
katlin95
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im not so sure how to do it?
jim_thompson5910
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or just write it out here
katlin95
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like what do you mean?
katlin95
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# 2 im not sure what to do
katlin95
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what is the first step i need to do @jim_thompson5910 ?
jim_thompson5910
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well start with what you are given
katlin95
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so would it be
BCD=EDC
BCD=ECD
katlin95
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both are given?
jim_thompson5910
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good, start off saying those two sets of angles are congruent because that's given
katlin95
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so then it would look like this?
BCD=EDC|GIVEN
BCD=ECD|GIVEN
and then now what?
jim_thompson5910
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what segments can you say for sure are congruent
katlin95
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uuhmm not so sure.
katlin95
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i would have to say that BCD and BED are congruent right?
jim_thompson5910
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what segment is between angles BCD and EDC
katlin95
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is it just one segment?
jim_thompson5910
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yes do you see it?
katlin95
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CDE?
jim_thompson5910
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segment, not angle
katlin95
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F?
jim_thompson5910
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that's a point, not a segment
katlin95
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whats a segment?
jim_thompson5910
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there's the figure
|dw:1358891844771:dw|
jim_thompson5910
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what I'm talking about is this segment (in black)
|dw:1358891880746:dw|
katlin95
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ohhh C and D sorry lol
jim_thompson5910
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you mean segment CD right?
katlin95
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yes hhaha lol
jim_thompson5910
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that's the shared side between the two triangles that overlap
jim_thompson5910
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CD = CD by the reflexive property
jim_thompson5910
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then you can say those two overlapping triangles are congruent by the ASA property
katlin95
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okay, so what would our whole overall problem look like? ill do it, and you see if it looks correct
jim_thompson5910
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alright
katlin95
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BCD=EDC|GIVEN
BCD=ECD|GIVEN
so CD=CD by the reflexive property
the two overlapping triangles are congruent by the ASA property
would this be what it look like?
jim_thompson5910
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you'll have to be specific by actually naming the triangles
katlin95
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BCD=EDC|GIVEN
BCD=ECD|GIVEN
so CD=CD by the reflexive property
BCD and EDC are congruent by the ASA property
how about this?^^
jim_thompson5910
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you nailed it
katlin95
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awesome! okay how about the next one now:)
jim_thompson5910
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oh you might want to say triangles BCD and EDC are congruent by the ASA property
so you don't confuse them with angles
katlin95
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okay!
jim_thompson5910
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ok how do we get started on the next one
katlin95
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we have to start with what we are given.
jim_thompson5910
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exactly, so go ahead and state that
katlin95
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im not sure how that to start this one because Ive never done one with a midpoint in it, but ill try real quik
jim_thompson5910
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well you start off by stating that D is the midpoint of AC (given)
then you use the definition of midpoint to say that AD = CD
katlin95
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BDC=BDA|GIVEN
BCD=BAD|GIVEN
RIGHT?
jim_thompson5910
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where does it say that BCD=BAD is given?
katlin95
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actually no lol
jim_thompson5910
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but the first one is given
jim_thompson5910
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so add that on
katlin95
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AD=CD|GIVEN
right?
jim_thompson5910
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AD = CD not because it's given, but by the definition of midpoint
jim_thompson5910
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A midpoint cuts a line segment into two equal halves
katlin95
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so then how do i find my other given?
jim_thompson5910
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You're done with you're givens
katlin95
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oh so theirs only one given then
jim_thompson5910
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Now you need one more side or one more angle, here is a visual hint:
|dw:1358892974213:dw|
jim_thompson5910
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There are 2 givens, but you've used them up already
katlin95
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so then if we have BDC=BDA|GIVEN
I would have to look at the other angle i have on the picture to get my other given?
jim_thompson5910
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|dw:1358893179414:dw|
katlin95
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BAD=BCD ?
jim_thompson5910
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see those segments i highlighted?
katlin95
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yep
jim_thompson5910
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they are congruent, do you see why?
katlin95
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yes, because they have equal sides right?
jim_thompson5910
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they are congruent because they are the same segment BD
|dw:1358893344746:dw|
jim_thompson5910
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so you'll have to say BD = BD and give a reason why that's true
katlin95
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so I would say BD=BD are reflective property ?
katlin95
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okay and then I say why my triangles are congruent?
jim_thompson5910
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yes and which property will you use
jim_thompson5910
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this may help
|dw:1358893552844:dw|
katlin95
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so then it would look like this:
BDC=BDA|GIVEN
So BD=BD by the reflective property
Triangles BDC and BDA are congruent by the ASA property
is this right?
jim_thompson5910
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you're missing something
jim_thompson5910
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AD = DC but why is that?
jim_thompson5910
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and remember you have 2 given statements
katlin95
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because its the midpoint, where would i place it?
jim_thompson5910
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and it's not the ASA property
katlin95
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would it be the SAS property?
jim_thompson5910
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yes that's correct
katlin95
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BDC=BDA|GIVEN
AD = DC|GIVEN
So BD=BD by the reflective property
Triangles BDC and BDA are congruent by the SAS property
jim_thompson5910
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no AD = DC is not given
jim_thompson5910
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go back and look at the doc and you'll see it's not given
katlin95
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okay, so then what would our next given be and is SAS correct for the property?
jim_thompson5910
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yes it's SAS
jim_thompson5910
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look back at the doc, and simply restate what they give
katlin95
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all i see is Dis the midpoint of side AC, and then BDC=BDA
jim_thompson5910
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there you go
jim_thompson5910
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just restate those and say given
jim_thompson5910
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that will allow you say that AD = DC because of the definition of midpoint
katlin95
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so how would it look ?
jim_thompson5910
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like you had it, just add those lines in
katlin95
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okay, where would I put that at when i put my answer in?
katlin95
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so would it look like this:
BDC=BDA|GIVEN
side AD =side DC|GIVEN
So BD=BD by the reflective property
Triangles BDC and BDA are congruent by the SAS property
jim_thompson5910
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put those givens at the top, then put AD = DC | definition of midpoint right after that
katlin95
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oh okay!
katlin95
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AD = DC | definition of midpoint
BDC=BDA|GIVEN
So BD=BD by the reflective property
Triangles BDC and BDA are congruent by the SAS property
jim_thompson5910
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you forgot AD = DC | definition of midpoint again
katlin95
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BDC=BDA|GIVEN
AD=DC|GIVEN
AD = DC | definition of midpoint
So BD=BD by the reflective property
Triangles BDC and BDA are congruent by the SAS property
katlin95
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OK last one!:)
jim_thompson5910
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ok show me what you got for this one
katlin95
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kk
katlin95
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I got:
AB=CD|GIVEN
BF=ED|GIVEN
is this right?
jim_thompson5910
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AB || CD, not AB = CD
jim_thompson5910
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also, angle B = angle D | given
katlin95
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so then it would look like this
AB||CD|GIVEN
angle B=angle D|given
jim_thompson5910
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along with BF=ED|GIVEN
jim_thompson5910
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you have 3 given statements
katlin95
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oh how would i order them?
jim_thompson5910
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in any order, all 3 are given and don't depend on one another
katlin95
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AB||CD|GIVEN
angle B=angle D|given
BF=ED|GIVEN
now what?
jim_thompson5910
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because AB || CD, we can say that
angle BAF = angle DCE
because they are alternate interior angles
jim_thompson5910
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so essentially
angle BAF = angle DCE | alternate interior angles
what's next?
jim_thompson5910
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you have 2 angles, and a side, which congruence property can you use?
katlin95
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BAF=angle DCE|alternate interior angles
angle B=angle D|given
BF=ED|GIVEN
just to clear it up is this right^^ if its not can you correct it?
jim_thompson5910
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you put the givens first though
the "given" statements always come first
jim_thompson5910
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since you always start with what you are given
jim_thompson5910
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and you build from there
katlin95
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BF=ED|GIVEN
angle B=angle D|given
BAF=angle DCE|alternate interior angles
jim_thompson5910
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you forgot the line AB||CD | given
katlin95
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where do i put that that at
jim_thompson5910
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above the "alternate interior angles" line
katlin95
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BF=ED|GIVEN
angle B=angle D|given
AB||CD | given
BAF=angle DCE|alternate interior angles
katlin95
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okay now what:)
jim_thompson5910
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you have 2 angles, and a side, which congruence property can you use?
katlin95
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ASA OR AAS
jim_thompson5910
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you would use AAS because the two angles are adjacent and the last side is not between them
katlin95
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Ok, so then would i say anything about reflective property?
jim_thompson5910
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no you can't use the reflexive property for this one
katlin95
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so it looks like this:
BF=ED|GIVEN
angle B=angle D|given
AB||CD | given
BAF=angle DCE|alternate interior angles
triangle BF and ED are congruent by the AAS property
jim_thompson5910
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last line is more like
triangle ABF and triangle CDE are congruent by the AAS property
katlin95
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okay, but otherwise it looks good?
jim_thompson5910
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yes it looks great
katlin95
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thanks so much jim! you tha best:))
jim_thompson5910
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you're welcome