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katlin95 Group Title

can someone help me with these 3 proofs, I have attached the file.. it has to get done by today! and i really appreciate it:) medals rewarded!

  • one year ago
  • one year ago

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  1. katlin95 Group Title
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    • one year ago
  2. katlin95 Group Title
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    @roberman228

    • one year ago
  3. katlin95 Group Title
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    okay:)

    • one year ago
  4. katlin95 Group Title
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    yea, ive tried google

    • one year ago
  5. katlin95 Group Title
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    @whpalmer4 can you help?

    • one year ago
  6. katlin95 Group Title
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    @jim_thompson5910 can you help me with these couple of questions about geometry proofs?

    • one year ago
  7. jim_thompson5910 Group Title
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    how far did you get on #2

    • one year ago
  8. katlin95 Group Title
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    um i think i finished that one, not sure let me check

    • one year ago
  9. jim_thompson5910 Group Title
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    ok post what you got

    • one year ago
  10. katlin95 Group Title
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    im not so sure how to do it?

    • one year ago
  11. jim_thompson5910 Group Title
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    or just write it out here

    • one year ago
  12. katlin95 Group Title
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    like what do you mean?

    • one year ago
  13. katlin95 Group Title
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    # 2 im not sure what to do

    • one year ago
  14. katlin95 Group Title
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    what is the first step i need to do @jim_thompson5910 ?

    • one year ago
  15. jim_thompson5910 Group Title
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    well start with what you are given

    • one year ago
  16. katlin95 Group Title
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    so would it be BCD=EDC BCD=ECD

    • one year ago
  17. katlin95 Group Title
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    both are given?

    • one year ago
  18. jim_thompson5910 Group Title
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    good, start off saying those two sets of angles are congruent because that's given

    • one year ago
  19. katlin95 Group Title
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    so then it would look like this? BCD=EDC|GIVEN BCD=ECD|GIVEN and then now what?

    • one year ago
  20. jim_thompson5910 Group Title
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    what segments can you say for sure are congruent

    • one year ago
  21. katlin95 Group Title
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    uuhmm not so sure.

    • one year ago
  22. katlin95 Group Title
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    i would have to say that BCD and BED are congruent right?

    • one year ago
  23. jim_thompson5910 Group Title
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    what segment is between angles BCD and EDC

    • one year ago
  24. katlin95 Group Title
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    is it just one segment?

    • one year ago
  25. jim_thompson5910 Group Title
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    yes do you see it?

    • one year ago
  26. katlin95 Group Title
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    CDE?

    • one year ago
  27. jim_thompson5910 Group Title
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    segment, not angle

    • one year ago
  28. katlin95 Group Title
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    F?

    • one year ago
  29. jim_thompson5910 Group Title
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    that's a point, not a segment

    • one year ago
  30. katlin95 Group Title
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    whats a segment?

    • one year ago
  31. jim_thompson5910 Group Title
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    there's the figure |dw:1358891844771:dw|

    • one year ago
  32. jim_thompson5910 Group Title
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    what I'm talking about is this segment (in black) |dw:1358891880746:dw|

    • one year ago
  33. katlin95 Group Title
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    ohhh C and D sorry lol

    • one year ago
  34. jim_thompson5910 Group Title
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    you mean segment CD right?

    • one year ago
  35. katlin95 Group Title
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    yes hhaha lol

    • one year ago
  36. jim_thompson5910 Group Title
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    that's the shared side between the two triangles that overlap

    • one year ago
  37. jim_thompson5910 Group Title
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    CD = CD by the reflexive property

    • one year ago
  38. jim_thompson5910 Group Title
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    then you can say those two overlapping triangles are congruent by the ASA property

    • one year ago
  39. katlin95 Group Title
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    okay, so what would our whole overall problem look like? ill do it, and you see if it looks correct

    • one year ago
  40. jim_thompson5910 Group Title
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    alright

    • one year ago
  41. katlin95 Group Title
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    BCD=EDC|GIVEN BCD=ECD|GIVEN so CD=CD by the reflexive property the two overlapping triangles are congruent by the ASA property would this be what it look like?

    • one year ago
  42. jim_thompson5910 Group Title
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    you'll have to be specific by actually naming the triangles

    • one year ago
  43. katlin95 Group Title
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    BCD=EDC|GIVEN BCD=ECD|GIVEN so CD=CD by the reflexive property BCD and EDC are congruent by the ASA property how about this?^^

    • one year ago
  44. jim_thompson5910 Group Title
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    you nailed it

    • one year ago
  45. katlin95 Group Title
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    awesome! okay how about the next one now:)

    • one year ago
  46. jim_thompson5910 Group Title
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    oh you might want to say triangles BCD and EDC are congruent by the ASA property so you don't confuse them with angles

    • one year ago
  47. katlin95 Group Title
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    okay!

    • one year ago
  48. jim_thompson5910 Group Title
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    ok how do we get started on the next one

    • one year ago
  49. katlin95 Group Title
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    we have to start with what we are given.

    • one year ago
  50. jim_thompson5910 Group Title
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    exactly, so go ahead and state that

    • one year ago
  51. katlin95 Group Title
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    im not sure how that to start this one because Ive never done one with a midpoint in it, but ill try real quik

    • one year ago
  52. jim_thompson5910 Group Title
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    well you start off by stating that D is the midpoint of AC (given) then you use the definition of midpoint to say that AD = CD

    • one year ago
  53. katlin95 Group Title
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    BDC=BDA|GIVEN BCD=BAD|GIVEN RIGHT?

    • one year ago
  54. jim_thompson5910 Group Title
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    where does it say that BCD=BAD is given?

    • one year ago
  55. katlin95 Group Title
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    actually no lol

    • one year ago
  56. jim_thompson5910 Group Title
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    but the first one is given

    • one year ago
  57. jim_thompson5910 Group Title
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    so add that on

    • one year ago
  58. katlin95 Group Title
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    AD=CD|GIVEN right?

    • one year ago
  59. jim_thompson5910 Group Title
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    AD = CD not because it's given, but by the definition of midpoint

    • one year ago
  60. jim_thompson5910 Group Title
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    A midpoint cuts a line segment into two equal halves

    • one year ago
  61. katlin95 Group Title
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    so then how do i find my other given?

    • one year ago
  62. jim_thompson5910 Group Title
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    You're done with you're givens

    • one year ago
  63. katlin95 Group Title
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    oh so theirs only one given then

    • one year ago
  64. jim_thompson5910 Group Title
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    Now you need one more side or one more angle, here is a visual hint: |dw:1358892974213:dw|

    • one year ago
  65. jim_thompson5910 Group Title
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    There are 2 givens, but you've used them up already

    • one year ago
  66. katlin95 Group Title
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    so then if we have BDC=BDA|GIVEN I would have to look at the other angle i have on the picture to get my other given?

    • one year ago
  67. jim_thompson5910 Group Title
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    |dw:1358893179414:dw|

    • one year ago
  68. katlin95 Group Title
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    BAD=BCD ?

    • one year ago
  69. jim_thompson5910 Group Title
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    see those segments i highlighted?

    • one year ago
  70. katlin95 Group Title
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    yep

    • one year ago
  71. jim_thompson5910 Group Title
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    they are congruent, do you see why?

    • one year ago
  72. katlin95 Group Title
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    yes, because they have equal sides right?

    • one year ago
  73. jim_thompson5910 Group Title
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    they are congruent because they are the same segment BD |dw:1358893344746:dw|

    • one year ago
  74. jim_thompson5910 Group Title
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    so you'll have to say BD = BD and give a reason why that's true

    • one year ago
  75. katlin95 Group Title
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    so I would say BD=BD are reflective property ?

    • one year ago
  76. jim_thompson5910 Group Title
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    good

    • one year ago
  77. katlin95 Group Title
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    okay and then I say why my triangles are congruent?

    • one year ago
  78. jim_thompson5910 Group Title
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    yes and which property will you use

    • one year ago
  79. jim_thompson5910 Group Title
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    this may help |dw:1358893552844:dw|

    • one year ago
  80. katlin95 Group Title
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    so then it would look like this: BDC=BDA|GIVEN So BD=BD by the reflective property Triangles BDC and BDA are congruent by the ASA property is this right?

    • one year ago
  81. jim_thompson5910 Group Title
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    you're missing something

    • one year ago
  82. jim_thompson5910 Group Title
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    AD = DC but why is that?

    • one year ago
  83. jim_thompson5910 Group Title
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    and remember you have 2 given statements

    • one year ago
  84. katlin95 Group Title
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    because its the midpoint, where would i place it?

    • one year ago
  85. jim_thompson5910 Group Title
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    and it's not the ASA property

    • one year ago
  86. katlin95 Group Title
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    would it be the SAS property?

    • one year ago
  87. jim_thompson5910 Group Title
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    yes that's correct

    • one year ago
  88. katlin95 Group Title
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    BDC=BDA|GIVEN AD = DC|GIVEN So BD=BD by the reflective property Triangles BDC and BDA are congruent by the SAS property

    • one year ago
  89. jim_thompson5910 Group Title
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    no AD = DC is not given

    • one year ago
  90. jim_thompson5910 Group Title
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    go back and look at the doc and you'll see it's not given

    • one year ago
  91. katlin95 Group Title
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    okay, so then what would our next given be and is SAS correct for the property?

    • one year ago
  92. jim_thompson5910 Group Title
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    yes it's SAS

    • one year ago
  93. jim_thompson5910 Group Title
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    look back at the doc, and simply restate what they give

    • one year ago
  94. katlin95 Group Title
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    all i see is Dis the midpoint of side AC, and then BDC=BDA

    • one year ago
  95. jim_thompson5910 Group Title
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    there you go

    • one year ago
  96. jim_thompson5910 Group Title
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    just restate those and say given

    • one year ago
  97. jim_thompson5910 Group Title
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    that will allow you say that AD = DC because of the definition of midpoint

    • one year ago
  98. katlin95 Group Title
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    so how would it look ?

    • one year ago
  99. jim_thompson5910 Group Title
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    like you had it, just add those lines in

    • one year ago
  100. katlin95 Group Title
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    okay, where would I put that at when i put my answer in?

    • one year ago
  101. katlin95 Group Title
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    so would it look like this: BDC=BDA|GIVEN side AD =side DC|GIVEN So BD=BD by the reflective property Triangles BDC and BDA are congruent by the SAS property

    • one year ago
  102. jim_thompson5910 Group Title
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    put those givens at the top, then put AD = DC | definition of midpoint right after that

    • one year ago
  103. katlin95 Group Title
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    oh okay!

    • one year ago
  104. katlin95 Group Title
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    AD = DC | definition of midpoint BDC=BDA|GIVEN So BD=BD by the reflective property Triangles BDC and BDA are congruent by the SAS property

    • one year ago
  105. jim_thompson5910 Group Title
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    you forgot AD = DC | definition of midpoint again

    • one year ago
  106. katlin95 Group Title
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    BDC=BDA|GIVEN AD=DC|GIVEN AD = DC | definition of midpoint So BD=BD by the reflective property Triangles BDC and BDA are congruent by the SAS property

    • one year ago
  107. jim_thompson5910 Group Title
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    good

    • one year ago
  108. katlin95 Group Title
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    OK last one!:)

    • one year ago
  109. jim_thompson5910 Group Title
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    ok show me what you got for this one

    • one year ago
  110. katlin95 Group Title
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    kk

    • one year ago
  111. katlin95 Group Title
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    I got: AB=CD|GIVEN BF=ED|GIVEN is this right?

    • one year ago
  112. jim_thompson5910 Group Title
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    AB || CD, not AB = CD

    • one year ago
  113. jim_thompson5910 Group Title
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    also, angle B = angle D | given

    • one year ago
  114. katlin95 Group Title
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    so then it would look like this AB||CD|GIVEN angle B=angle D|given

    • one year ago
  115. jim_thompson5910 Group Title
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    along with BF=ED|GIVEN

    • one year ago
  116. jim_thompson5910 Group Title
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    you have 3 given statements

    • one year ago
  117. katlin95 Group Title
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    oh how would i order them?

    • one year ago
  118. jim_thompson5910 Group Title
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    in any order, all 3 are given and don't depend on one another

    • one year ago
  119. katlin95 Group Title
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    AB||CD|GIVEN angle B=angle D|given BF=ED|GIVEN now what?

    • one year ago
  120. jim_thompson5910 Group Title
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    because AB || CD, we can say that angle BAF = angle DCE because they are alternate interior angles

    • one year ago
  121. jim_thompson5910 Group Title
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    so essentially angle BAF = angle DCE | alternate interior angles what's next?

    • one year ago
  122. jim_thompson5910 Group Title
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    you have 2 angles, and a side, which congruence property can you use?

    • one year ago
  123. katlin95 Group Title
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    BAF=angle DCE|alternate interior angles angle B=angle D|given BF=ED|GIVEN just to clear it up is this right^^ if its not can you correct it?

    • one year ago
  124. jim_thompson5910 Group Title
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    you put the givens first though the "given" statements always come first

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  125. jim_thompson5910 Group Title
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    since you always start with what you are given

    • one year ago
  126. jim_thompson5910 Group Title
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    and you build from there

    • one year ago
  127. katlin95 Group Title
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    BF=ED|GIVEN angle B=angle D|given BAF=angle DCE|alternate interior angles

    • one year ago
  128. jim_thompson5910 Group Title
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    you forgot the line AB||CD | given

    • one year ago
  129. katlin95 Group Title
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    where do i put that that at

    • one year ago
  130. jim_thompson5910 Group Title
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    above the "alternate interior angles" line

    • one year ago
  131. katlin95 Group Title
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    BF=ED|GIVEN angle B=angle D|given AB||CD | given BAF=angle DCE|alternate interior angles

    • one year ago
  132. jim_thompson5910 Group Title
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    good

    • one year ago
  133. katlin95 Group Title
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    okay now what:)

    • one year ago
  134. jim_thompson5910 Group Title
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    you have 2 angles, and a side, which congruence property can you use?

    • one year ago
  135. katlin95 Group Title
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    ASA OR AAS

    • one year ago
  136. jim_thompson5910 Group Title
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    you would use AAS because the two angles are adjacent and the last side is not between them

    • one year ago
  137. katlin95 Group Title
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    Ok, so then would i say anything about reflective property?

    • one year ago
  138. jim_thompson5910 Group Title
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    no you can't use the reflexive property for this one

    • one year ago
  139. katlin95 Group Title
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    so it looks like this: BF=ED|GIVEN angle B=angle D|given AB||CD | given BAF=angle DCE|alternate interior angles triangle BF and ED are congruent by the AAS property

    • one year ago
  140. jim_thompson5910 Group Title
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    last line is more like triangle ABF and triangle CDE are congruent by the AAS property

    • one year ago
  141. katlin95 Group Title
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    okay, but otherwise it looks good?

    • one year ago
  142. jim_thompson5910 Group Title
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    yes it looks great

    • one year ago
  143. katlin95 Group Title
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    thanks so much jim! you tha best:))

    • one year ago
  144. jim_thompson5910 Group Title
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    you're welcome

    • one year ago
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