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katlin95

  • 3 years ago

can someone help me with these 3 proofs, I have attached the file.. it has to get done by today! and i really appreciate it:) medals rewarded!

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  1. katlin95
    • 3 years ago
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  2. katlin95
    • 3 years ago
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    @roberman228

  3. katlin95
    • 3 years ago
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    okay:)

  4. katlin95
    • 3 years ago
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    yea, ive tried google

  5. katlin95
    • 3 years ago
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    @whpalmer4 can you help?

  6. katlin95
    • 3 years ago
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    @jim_thompson5910 can you help me with these couple of questions about geometry proofs?

  7. jim_thompson5910
    • 3 years ago
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    how far did you get on #2

  8. katlin95
    • 3 years ago
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    um i think i finished that one, not sure let me check

  9. jim_thompson5910
    • 3 years ago
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    ok post what you got

  10. katlin95
    • 3 years ago
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    im not so sure how to do it?

  11. jim_thompson5910
    • 3 years ago
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    or just write it out here

  12. katlin95
    • 3 years ago
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    like what do you mean?

  13. katlin95
    • 3 years ago
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    # 2 im not sure what to do

  14. katlin95
    • 3 years ago
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    what is the first step i need to do @jim_thompson5910 ?

  15. jim_thompson5910
    • 3 years ago
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    well start with what you are given

  16. katlin95
    • 3 years ago
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    so would it be BCD=EDC BCD=ECD

  17. katlin95
    • 3 years ago
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    both are given?

  18. jim_thompson5910
    • 3 years ago
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    good, start off saying those two sets of angles are congruent because that's given

  19. katlin95
    • 3 years ago
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    so then it would look like this? BCD=EDC|GIVEN BCD=ECD|GIVEN and then now what?

  20. jim_thompson5910
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    what segments can you say for sure are congruent

  21. katlin95
    • 3 years ago
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    uuhmm not so sure.

  22. katlin95
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    i would have to say that BCD and BED are congruent right?

  23. jim_thompson5910
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    what segment is between angles BCD and EDC

  24. katlin95
    • 3 years ago
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    is it just one segment?

  25. jim_thompson5910
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    yes do you see it?

  26. katlin95
    • 3 years ago
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    CDE?

  27. jim_thompson5910
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    segment, not angle

  28. katlin95
    • 3 years ago
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    F?

  29. jim_thompson5910
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    that's a point, not a segment

  30. katlin95
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    whats a segment?

  31. jim_thompson5910
    • 3 years ago
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    there's the figure |dw:1358891844771:dw|

  32. jim_thompson5910
    • 3 years ago
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    what I'm talking about is this segment (in black) |dw:1358891880746:dw|

  33. katlin95
    • 3 years ago
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    ohhh C and D sorry lol

  34. jim_thompson5910
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    you mean segment CD right?

  35. katlin95
    • 3 years ago
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    yes hhaha lol

  36. jim_thompson5910
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    that's the shared side between the two triangles that overlap

  37. jim_thompson5910
    • 3 years ago
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    CD = CD by the reflexive property

  38. jim_thompson5910
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    then you can say those two overlapping triangles are congruent by the ASA property

  39. katlin95
    • 3 years ago
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    okay, so what would our whole overall problem look like? ill do it, and you see if it looks correct

  40. jim_thompson5910
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    alright

  41. katlin95
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    BCD=EDC|GIVEN BCD=ECD|GIVEN so CD=CD by the reflexive property the two overlapping triangles are congruent by the ASA property would this be what it look like?

  42. jim_thompson5910
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    you'll have to be specific by actually naming the triangles

  43. katlin95
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    BCD=EDC|GIVEN BCD=ECD|GIVEN so CD=CD by the reflexive property BCD and EDC are congruent by the ASA property how about this?^^

  44. jim_thompson5910
    • 3 years ago
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    you nailed it

  45. katlin95
    • 3 years ago
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    awesome! okay how about the next one now:)

  46. jim_thompson5910
    • 3 years ago
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    oh you might want to say triangles BCD and EDC are congruent by the ASA property so you don't confuse them with angles

  47. katlin95
    • 3 years ago
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    okay!

  48. jim_thompson5910
    • 3 years ago
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    ok how do we get started on the next one

  49. katlin95
    • 3 years ago
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    we have to start with what we are given.

  50. jim_thompson5910
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    exactly, so go ahead and state that

  51. katlin95
    • 3 years ago
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    im not sure how that to start this one because Ive never done one with a midpoint in it, but ill try real quik

  52. jim_thompson5910
    • 3 years ago
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    well you start off by stating that D is the midpoint of AC (given) then you use the definition of midpoint to say that AD = CD

  53. katlin95
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    BDC=BDA|GIVEN BCD=BAD|GIVEN RIGHT?

  54. jim_thompson5910
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    where does it say that BCD=BAD is given?

  55. katlin95
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    actually no lol

  56. jim_thompson5910
    • 3 years ago
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    but the first one is given

  57. jim_thompson5910
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    so add that on

  58. katlin95
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    AD=CD|GIVEN right?

  59. jim_thompson5910
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    AD = CD not because it's given, but by the definition of midpoint

  60. jim_thompson5910
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    A midpoint cuts a line segment into two equal halves

  61. katlin95
    • 3 years ago
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    so then how do i find my other given?

  62. jim_thompson5910
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    You're done with you're givens

  63. katlin95
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    oh so theirs only one given then

  64. jim_thompson5910
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    Now you need one more side or one more angle, here is a visual hint: |dw:1358892974213:dw|

  65. jim_thompson5910
    • 3 years ago
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    There are 2 givens, but you've used them up already

  66. katlin95
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    so then if we have BDC=BDA|GIVEN I would have to look at the other angle i have on the picture to get my other given?

  67. jim_thompson5910
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    |dw:1358893179414:dw|

  68. katlin95
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    BAD=BCD ?

  69. jim_thompson5910
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    see those segments i highlighted?

  70. katlin95
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    yep

  71. jim_thompson5910
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    they are congruent, do you see why?

  72. katlin95
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    yes, because they have equal sides right?

  73. jim_thompson5910
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    they are congruent because they are the same segment BD |dw:1358893344746:dw|

  74. jim_thompson5910
    • 3 years ago
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    so you'll have to say BD = BD and give a reason why that's true

  75. katlin95
    • 3 years ago
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    so I would say BD=BD are reflective property ?

  76. jim_thompson5910
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    good

  77. katlin95
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    okay and then I say why my triangles are congruent?

  78. jim_thompson5910
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    yes and which property will you use

  79. jim_thompson5910
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    this may help |dw:1358893552844:dw|

  80. katlin95
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    so then it would look like this: BDC=BDA|GIVEN So BD=BD by the reflective property Triangles BDC and BDA are congruent by the ASA property is this right?

  81. jim_thompson5910
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    you're missing something

  82. jim_thompson5910
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    AD = DC but why is that?

  83. jim_thompson5910
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    and remember you have 2 given statements

  84. katlin95
    • 3 years ago
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    because its the midpoint, where would i place it?

  85. jim_thompson5910
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    and it's not the ASA property

  86. katlin95
    • 3 years ago
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    would it be the SAS property?

  87. jim_thompson5910
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    yes that's correct

  88. katlin95
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    BDC=BDA|GIVEN AD = DC|GIVEN So BD=BD by the reflective property Triangles BDC and BDA are congruent by the SAS property

  89. jim_thompson5910
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    no AD = DC is not given

  90. jim_thompson5910
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    go back and look at the doc and you'll see it's not given

  91. katlin95
    • 3 years ago
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    okay, so then what would our next given be and is SAS correct for the property?

  92. jim_thompson5910
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    yes it's SAS

  93. jim_thompson5910
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    look back at the doc, and simply restate what they give

  94. katlin95
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    all i see is Dis the midpoint of side AC, and then BDC=BDA

  95. jim_thompson5910
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    there you go

  96. jim_thompson5910
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    just restate those and say given

  97. jim_thompson5910
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    that will allow you say that AD = DC because of the definition of midpoint

  98. katlin95
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    so how would it look ?

  99. jim_thompson5910
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    like you had it, just add those lines in

  100. katlin95
    • 3 years ago
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    okay, where would I put that at when i put my answer in?

  101. katlin95
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    so would it look like this: BDC=BDA|GIVEN side AD =side DC|GIVEN So BD=BD by the reflective property Triangles BDC and BDA are congruent by the SAS property

  102. jim_thompson5910
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    put those givens at the top, then put AD = DC | definition of midpoint right after that

  103. katlin95
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    oh okay!

  104. katlin95
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    AD = DC | definition of midpoint BDC=BDA|GIVEN So BD=BD by the reflective property Triangles BDC and BDA are congruent by the SAS property

  105. jim_thompson5910
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    you forgot AD = DC | definition of midpoint again

  106. katlin95
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    BDC=BDA|GIVEN AD=DC|GIVEN AD = DC | definition of midpoint So BD=BD by the reflective property Triangles BDC and BDA are congruent by the SAS property

  107. jim_thompson5910
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    good

  108. katlin95
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    OK last one!:)

  109. jim_thompson5910
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    ok show me what you got for this one

  110. katlin95
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    kk

  111. katlin95
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    I got: AB=CD|GIVEN BF=ED|GIVEN is this right?

  112. jim_thompson5910
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    AB || CD, not AB = CD

  113. jim_thompson5910
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    also, angle B = angle D | given

  114. katlin95
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    so then it would look like this AB||CD|GIVEN angle B=angle D|given

  115. jim_thompson5910
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    along with BF=ED|GIVEN

  116. jim_thompson5910
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    you have 3 given statements

  117. katlin95
    • 3 years ago
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    oh how would i order them?

  118. jim_thompson5910
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    in any order, all 3 are given and don't depend on one another

  119. katlin95
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    AB||CD|GIVEN angle B=angle D|given BF=ED|GIVEN now what?

  120. jim_thompson5910
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    because AB || CD, we can say that angle BAF = angle DCE because they are alternate interior angles

  121. jim_thompson5910
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    so essentially angle BAF = angle DCE | alternate interior angles what's next?

  122. jim_thompson5910
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    you have 2 angles, and a side, which congruence property can you use?

  123. katlin95
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    BAF=angle DCE|alternate interior angles angle B=angle D|given BF=ED|GIVEN just to clear it up is this right^^ if its not can you correct it?

  124. jim_thompson5910
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    you put the givens first though the "given" statements always come first

  125. jim_thompson5910
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    since you always start with what you are given

  126. jim_thompson5910
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    and you build from there

  127. katlin95
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    BF=ED|GIVEN angle B=angle D|given BAF=angle DCE|alternate interior angles

  128. jim_thompson5910
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    you forgot the line AB||CD | given

  129. katlin95
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    where do i put that that at

  130. jim_thompson5910
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    above the "alternate interior angles" line

  131. katlin95
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    BF=ED|GIVEN angle B=angle D|given AB||CD | given BAF=angle DCE|alternate interior angles

  132. jim_thompson5910
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    good

  133. katlin95
    • 3 years ago
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    okay now what:)

  134. jim_thompson5910
    • 3 years ago
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    you have 2 angles, and a side, which congruence property can you use?

  135. katlin95
    • 3 years ago
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    ASA OR AAS

  136. jim_thompson5910
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    you would use AAS because the two angles are adjacent and the last side is not between them

  137. katlin95
    • 3 years ago
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    Ok, so then would i say anything about reflective property?

  138. jim_thompson5910
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    no you can't use the reflexive property for this one

  139. katlin95
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    so it looks like this: BF=ED|GIVEN angle B=angle D|given AB||CD | given BAF=angle DCE|alternate interior angles triangle BF and ED are congruent by the AAS property

  140. jim_thompson5910
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    last line is more like triangle ABF and triangle CDE are congruent by the AAS property

  141. katlin95
    • 3 years ago
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    okay, but otherwise it looks good?

  142. jim_thompson5910
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    yes it looks great

  143. katlin95
    • 3 years ago
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    thanks so much jim! you tha best:))

  144. jim_thompson5910
    • 3 years ago
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    you're welcome

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