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Find the average value of the function f on the given interval. f(x)=√x on the interval [1,9] Please explain the process.

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You are dealing with the fundamental theorem of calculus pt. II. According to FToC II Suppose f(x) is a contunuous function on an interval [a, b] which in your case is [1,9]. and supposed that F(x) is any anti-derviateive for f(x). Then: \[\int\limits_{1}^{9}\sqrt{x}dx = F(x)\] where F(x) is evalauted on the inteval [1,9] meaning: \[F(b) - F (a) = F(9)-F(1)\]

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@amoodarya that's very helpful! Good job, but I think you should of let him try it out on his own first as this is a Calculus course which requires more critical thinking and application.
sorry for hurry
I'm trying to understand how to get the answer. Thanks both of you. :)
(emphasis on "how to") ;)
If there's any confusion, please ask. It's best to ask all the questions now and know for certain than be uncertain during an exam.
Thanks, I think I'm good for now, but I may come back to ask more questions.
It just occurred to me that the answer is wrong because I wanted it on the interval [1,9] not [0,9].
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