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anonymous
 4 years ago
method of least squares fit, y=Bx to the following n=6 points (3,4),(1,2),(5,4),(6,8),(3,6),(4,5) and it has to go through the origin can someone help me get started?
anonymous
 4 years ago
method of least squares fit, y=Bx to the following n=6 points (3,4),(1,2),(5,4),(6,8),(3,6),(4,5) and it has to go through the origin can someone help me get started?

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tkhunny
 4 years ago
Best ResponseYou've already chosen the best response.1Did you answer the question last night? \(\sum{xy} = B\cdot\sum{x^{2}}\) Have you seen it? Can you create it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you have to minimize the B right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did you already get the summation etc without minimazing and taking derivatives?

tkhunny
 4 years ago
Best ResponseYou've already chosen the best response.1No, you are minimizing the error. You must select the B that accomplishes this task.

tkhunny
 4 years ago
Best ResponseYou've already chosen the best response.1You are asking good questions. This suggests that you have seen the development of Normal Equations.

tkhunny
 4 years ago
Best ResponseYou've already chosen the best response.1\(I(B) = \left(y  Bx\right)^{2}\) Find \(\dfrac{dI}{dB}\).

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I don't get how did you get the summation equation that you posted, i know how to solve it from there, but how did you figured it out so fast

tkhunny
 4 years ago
Best ResponseYou've already chosen the best response.1It doesn't matter, in this case. I just wanted to check to see that you had it right and were moving on.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the question is if there is other way to coming up with the equation to the problem you came up with, instead of going through the minimalization formula then partial derivative =0

tkhunny
 4 years ago
Best ResponseYou've already chosen the best response.1Well, there are some Matrix methods, but I'm guessing we don't want to talk about those, today. You have it just fine, excepting that this is a oneparameter derivation so it's just a Derivative, not a Partial Derivative. 2x(yBx) = 0 leads to what?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02Bx^2=+2xy B=2xy/2x^2 B=xy/x^2

tkhunny
 4 years ago
Best ResponseYou've already chosen the best response.1More importantly, \(xy = Bx^{2}\). Resist the temptation to solve for B. If you've more than one parameter, you WILL become confused. Reach for the standard Normal Equation form.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am not really familiar with Normal Equation yet

tkhunny
 4 years ago
Best ResponseYou've already chosen the best response.1Pretty much just: 1) Everything without a parameter on one side, and 2) Everything with a parameter on the other side  in ascending Order of the terms.

tkhunny
 4 years ago
Best ResponseYou've already chosen the best response.1Solving for y = a + bx comes out: y = a + bx yx = ax + bx^2 For example.
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