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you have to minimize the B right?

how did you already get the summation etc without minimazing and taking derivatives?

No, you are minimizing the error. You must select the B that accomplishes this task.

You are asking good questions. This suggests that you have seen the development of Normal Equations.

\(I(B) = \left(y - Bx\right)^{2}\)
Find \(\dfrac{dI}{dB}\).

2x(y-Bx)?

Negative x?

-2xy-2bx^2 =0

-2xy+Bx^2=0 sorry

2Bx^2=+2xy
B=2xy/2x^2
B=xy/x^2

ii see it now

i am not really familiar with Normal Equation yet

Solving for y = a + bx comes out:
y = a + bx
yx = ax + bx^2
For example.