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Check my work. Okay so I have a system of linear equations {y  2 = (1/3)x and 3y =  2x  3.
I need to get them into slope intercept form so I can graph them. Here is my answer: on the upper one we can add 2 to both sides. y  2 + 2 = 1/3x + 2 = y = 1/3x + 2. Now we need to get the second equation into slope intercept form. So we divide both sides by three. 3y/3 =  2x  3/3 = y =  2x  1
 one year ago
 one year ago
Check my work. Okay so I have a system of linear equations {y  2 = (1/3)x and 3y =  2x  3. I need to get them into slope intercept form so I can graph them. Here is my answer: on the upper one we can add 2 to both sides. y  2 + 2 = 1/3x + 2 = y = 1/3x + 2. Now we need to get the second equation into slope intercept form. So we divide both sides by three. 3y/3 =  2x  3/3 = y =  2x  1
 one year ago
 one year ago

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jim_thompson5910Best ResponseYou've already chosen the best response.1
the first one is correct the second is not
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
you need to divide every part by 3 so the second equation should be y = 2/3x  1
 one year ago
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