A community for students.
Here's the question you clicked on:
 0 viewing
aussy123
 2 years ago
Can someone explain this to me? I already know the answer, but I don't understand why its the answer.
Without solving the equation, determine the nature of the roots of x2  2x  8 = 0.
Two, real unequal roots
Two, real equal roots
No real roots
aussy123
 2 years ago
Can someone explain this to me? I already know the answer, but I don't understand why its the answer. Without solving the equation, determine the nature of the roots of x2  2x  8 = 0. Two, real unequal roots Two, real equal roots No real roots

This Question is Closed

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1\[ax^2+bx+c=0\]consider the discriminant \[\Delta=b^24ac\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1the discriminant is part of the quadratic formula \[x=\frac{b\pm\sqrt{\Delta}}{2a}\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1the quadratic formula takes plus and minus the square root of the discriminant, plus and minus a square root will have one value if the term in the square root is 0, two values if the term in the sqrt is positive, and no real values f the term in the square is negative

aussy123
 2 years ago
Best ResponseYou've already chosen the best response.0Okay thanks, this is a mouthful but I understand lol.

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1**and no real values if the term in the square root is negative

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1yeah it is a complicate formula
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.