determine the domain of \[f(x)=\sqrt{9-x ^{2}}\]

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determine the domain of \[f(x)=\sqrt{9-x ^{2}}\]

Mathematics
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What's your question? haha
determine the domain \[f(x)=\sqrt{9-x ^{2}}\]
Do you know what the question is asking for? i.e. do you know what the domain of a function is?

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the question just says determine the domain of \[f(x)=\sqrt{9-x ^{2}}\]
Yes I know. But do YOU know what it means? What is the "domain"
oh lol isnt it a set of functions with all possible inputs from neg to pos or infinite?
wouldn't i be breaking down the square root of 9 - x squared (3-x)(3+x)
It is all the values of x that you could put into your function to get an output value. So a better question would be to ask yourself what values of x can I put into the function that makes it DNE
what does DNE mean?
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DNE is 'does not exist' i.e refers to a part on the functions graph that cannot be determined, because it simply does not exist. :) Basically you need to watch out for square roots, logarithms and denominators equalling zero. In your case, you have a square root, and as @henryrodriguez713 pointed out, you CANNOT have a negative number under the square root.
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To get rid of the square root, simply square both sides of the equation.
oh since i can't have a negative number, the answer would be false correct? its been 3 years since i've been in school xD
The function does not exist for x values less than -3 and more than 3
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Haha. Don't worry if you haven't been in school for three years. All that really matters is that you're learning it. :D
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would this be the final product answer?

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