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Nanoman
Group Title
What is the volume of a solid obtained by rotating the region between the graph of y = (1/2)sin^2 (x^2) and the xaxis for 0 ≤x≤sqrtpi about the yaxis?
 one year ago
 one year ago
Nanoman Group Title
What is the volume of a solid obtained by rotating the region between the graph of y = (1/2)sin^2 (x^2) and the xaxis for 0 ≤x≤sqrtpi about the yaxis?
 one year ago
 one year ago

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Nanoman Group TitleBest ResponseYou've already chosen the best response.0
The main problem I have is that I can't solve for x.
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
Are you there?
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Put y =0 0 = (1/2)sin^2 (x^2) sin^2 (x^2) = 0 sin (x^2) = 0 x^2 =...???
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
0 is all I can think of.
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
dw:1358903484725:dw
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
Oh, right! Sine hits zero on every multiple of pi
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
So x = sqrt(pi), 0?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
For that domain, yes.
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
Right. The domain was a clue.
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
I need to use the washer method right?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
I think we need to use shell method?!
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
oh, right. just a sec....
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
x = sqrtpi for the radis, y = (1/2)sin^2 (x^2) for the height?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
x = radius... y = height
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
\[2\pi \int\limits_{0}^{\sqrt{\pi}} (\sqrt{\pi}/2) \sin^2 (x^2)\] ?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
\[V = 2 \pi \int_a^brh(width)\]r = x, h = y, width = dx
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
y is a function of x, you know.
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
Doesn't x = sqrtpi and y = (1/2)sin^2 (x^2)?
 one year ago
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