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 one year ago
What is the volume of a solid obtained by rotating the region between the graph of y = (1/2)sin^2 (x^2) and the xaxis for 0 ≤x≤sqrtpi about the yaxis?
 one year ago
What is the volume of a solid obtained by rotating the region between the graph of y = (1/2)sin^2 (x^2) and the xaxis for 0 ≤x≤sqrtpi about the yaxis?

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Nanoman
 one year ago
Best ResponseYou've already chosen the best response.0The main problem I have is that I can't solve for x.

Callisto
 one year ago
Best ResponseYou've already chosen the best response.0Put y =0 0 = (1/2)sin^2 (x^2) sin^2 (x^2) = 0 sin (x^2) = 0 x^2 =...???

Nanoman
 one year ago
Best ResponseYou've already chosen the best response.00 is all I can think of.

Callisto
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358903484725:dw

Nanoman
 one year ago
Best ResponseYou've already chosen the best response.0Oh, right! Sine hits zero on every multiple of pi

Callisto
 one year ago
Best ResponseYou've already chosen the best response.0For that domain, yes.

Nanoman
 one year ago
Best ResponseYou've already chosen the best response.0Right. The domain was a clue.

Nanoman
 one year ago
Best ResponseYou've already chosen the best response.0I need to use the washer method right?

Callisto
 one year ago
Best ResponseYou've already chosen the best response.0I think we need to use shell method?!

Nanoman
 one year ago
Best ResponseYou've already chosen the best response.0oh, right. just a sec....

Nanoman
 one year ago
Best ResponseYou've already chosen the best response.0x = sqrtpi for the radis, y = (1/2)sin^2 (x^2) for the height?

Callisto
 one year ago
Best ResponseYou've already chosen the best response.0x = radius... y = height

Nanoman
 one year ago
Best ResponseYou've already chosen the best response.0\[2\pi \int\limits_{0}^{\sqrt{\pi}} (\sqrt{\pi}/2) \sin^2 (x^2)\] ?

Callisto
 one year ago
Best ResponseYou've already chosen the best response.0\[V = 2 \pi \int_a^brh(width)\]r = x, h = y, width = dx

Callisto
 one year ago
Best ResponseYou've already chosen the best response.0y is a function of x, you know.

Nanoman
 one year ago
Best ResponseYou've already chosen the best response.0Doesn't x = sqrtpi and y = (1/2)sin^2 (x^2)?
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