A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
What is the volume of a solid obtained by rotating the region between the graph of y = (1/2)sin^2 (x^2) and the xaxis for 0 ≤x≤sqrtpi about the yaxis?
anonymous
 3 years ago
What is the volume of a solid obtained by rotating the region between the graph of y = (1/2)sin^2 (x^2) and the xaxis for 0 ≤x≤sqrtpi about the yaxis?

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The main problem I have is that I can't solve for x.

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0Put y =0 0 = (1/2)sin^2 (x^2) sin^2 (x^2) = 0 sin (x^2) = 0 x^2 =...???

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.00 is all I can think of.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, right! Sine hits zero on every multiple of pi

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Right. The domain was a clue.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I need to use the washer method right?

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0I think we need to use shell method?!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh, right. just a sec....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0x = sqrtpi for the radis, y = (1/2)sin^2 (x^2) for the height?

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0x = radius... y = height

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[2\pi \int\limits_{0}^{\sqrt{\pi}} (\sqrt{\pi}/2) \sin^2 (x^2)\] ?

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0\[V = 2 \pi \int_a^brh(width)\]r = x, h = y, width = dx

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0y is a function of x, you know.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Doesn't x = sqrtpi and y = (1/2)sin^2 (x^2)?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.