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Nanoman
 3 years ago
What is the volume of a solid obtained by rotating the region between the graph of y = (1/2)sin^2 (x^2) and the xaxis for 0 ≤x≤sqrtpi about the yaxis?
Nanoman
 3 years ago
What is the volume of a solid obtained by rotating the region between the graph of y = (1/2)sin^2 (x^2) and the xaxis for 0 ≤x≤sqrtpi about the yaxis?

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Nanoman
 3 years ago
Best ResponseYou've already chosen the best response.0The main problem I have is that I can't solve for x.

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0Put y =0 0 = (1/2)sin^2 (x^2) sin^2 (x^2) = 0 sin (x^2) = 0 x^2 =...???

Nanoman
 3 years ago
Best ResponseYou've already chosen the best response.00 is all I can think of.

Nanoman
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, right! Sine hits zero on every multiple of pi

Nanoman
 3 years ago
Best ResponseYou've already chosen the best response.0Right. The domain was a clue.

Nanoman
 3 years ago
Best ResponseYou've already chosen the best response.0I need to use the washer method right?

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0I think we need to use shell method?!

Nanoman
 3 years ago
Best ResponseYou've already chosen the best response.0oh, right. just a sec....

Nanoman
 3 years ago
Best ResponseYou've already chosen the best response.0x = sqrtpi for the radis, y = (1/2)sin^2 (x^2) for the height?

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0x = radius... y = height

Nanoman
 3 years ago
Best ResponseYou've already chosen the best response.0\[2\pi \int\limits_{0}^{\sqrt{\pi}} (\sqrt{\pi}/2) \sin^2 (x^2)\] ?

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0\[V = 2 \pi \int_a^brh(width)\]r = x, h = y, width = dx

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0y is a function of x, you know.

Nanoman
 3 years ago
Best ResponseYou've already chosen the best response.0Doesn't x = sqrtpi and y = (1/2)sin^2 (x^2)?
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