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need help solving some basic algebra question to the 3rd power!!
 one year ago
 one year ago
need help solving some basic algebra question to the 3rd power!!
 one year ago
 one year ago

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zhengcl86Best ResponseYou've already chosen the best response.0
\[8x ^{3}  4x ^{2 }  12x =0\]
 one year ago

zhengcl86Best ResponseYou've already chosen the best response.0
how would i break that down?
 one year ago

JohnnyRocketfingersBest ResponseYou've already chosen the best response.0
your trying to factor the polynomial
 one year ago

precalBest ResponseYou've already chosen the best response.1
if you look at your graph, these locations are where the graph crosses the x axis
 one year ago

precalBest ResponseYou've already chosen the best response.1
always try to factor equations back into linear or quadratics if that does not work then you have to use synthetic division
 one year ago

JohnnyRocketfingersBest ResponseYou've already chosen the best response.0
nice, it helped me.
 one year ago

zhengcl86Best ResponseYou've already chosen the best response.0
wow a bit confusing lol but something is clicking in my brain
 one year ago

precalBest ResponseYou've already chosen the best response.1
well remember you are only taught to factor 2nd powers. I factored out 4x because that created the 2nd power
 one year ago

zhengcl86Best ResponseYou've already chosen the best response.0
so its factored out then simplfied down?
 one year ago

precalBest ResponseYou've already chosen the best response.1
once you factor it, then we have a theorem that states we can set them to zero and solve each one
 one year ago

zhengcl86Best ResponseYou've already chosen the best response.0
when the 4x is factored out the 8x 3rd power becomes 2x 2nd power?
 one year ago

zhengcl86Best ResponseYou've already chosen the best response.0
was that divided by the 4x? and expondents substracted?
 one year ago

precalBest ResponseYou've already chosen the best response.1
not I factored it outdw:1358903718312:dwcheck yourself by distributing it back in
 one year ago
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