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zhengcl86

  • 3 years ago

need help solving some basic algebra question to the 3rd power!!

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  1. gianarpt
    • 3 years ago
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    what questions

  2. zhengcl86
    • 3 years ago
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    \[8x ^{3} - 4x ^{2 } - 12x =0\]

  3. zhengcl86
    • 3 years ago
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    how would i break that down?

  4. precal
    • 3 years ago
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    factor out the GCF

  5. precal
    • 3 years ago
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    I would factor out 4x

  6. JohnnyRocketfingers
    • 3 years ago
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    your trying to factor the polynomial

  7. precal
    • 3 years ago
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    |dw:1358903207710:dw|

  8. precal
    • 3 years ago
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    |dw:1358903232815:dw|

  9. precal
    • 3 years ago
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    |dw:1358903299195:dw|

  10. precal
    • 3 years ago
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    if you look at your graph, these locations are where the graph crosses the x axis

  11. precal
    • 3 years ago
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    always try to factor equations back into linear or quadratics if that does not work then you have to use synthetic division

  12. precal
    • 3 years ago
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    hope that helps you

  13. JohnnyRocketfingers
    • 3 years ago
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    nice, it helped me.

  14. zhengcl86
    • 3 years ago
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    wow a bit confusing lol but something is clicking in my brain

  15. precal
    • 3 years ago
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    well remember you are only taught to factor 2nd powers. I factored out 4x because that created the 2nd power

  16. zhengcl86
    • 3 years ago
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    so its factored out then simplfied down?

  17. precal
    • 3 years ago
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    once you factor it, then we have a theorem that states we can set them to zero and solve each one

  18. zhengcl86
    • 3 years ago
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    when the 4x is factored out the 8x 3rd power becomes 2x 2nd power?

  19. zhengcl86
    • 3 years ago
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    was that divided by the 4x? and expondents substracted?

  20. precal
    • 3 years ago
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    not I factored it out|dw:1358903718312:dw|check yourself by distributing it back in

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