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zhengcl86
 2 years ago
Best ResponseYou've already chosen the best response.0\[8x ^{3}  4x ^{2 }  12x =0\]

zhengcl86
 2 years ago
Best ResponseYou've already chosen the best response.0how would i break that down?

JohnnyRocketfingers
 2 years ago
Best ResponseYou've already chosen the best response.0your trying to factor the polynomial

precal
 2 years ago
Best ResponseYou've already chosen the best response.1if you look at your graph, these locations are where the graph crosses the x axis

precal
 2 years ago
Best ResponseYou've already chosen the best response.1always try to factor equations back into linear or quadratics if that does not work then you have to use synthetic division

JohnnyRocketfingers
 2 years ago
Best ResponseYou've already chosen the best response.0nice, it helped me.

zhengcl86
 2 years ago
Best ResponseYou've already chosen the best response.0wow a bit confusing lol but something is clicking in my brain

precal
 2 years ago
Best ResponseYou've already chosen the best response.1well remember you are only taught to factor 2nd powers. I factored out 4x because that created the 2nd power

zhengcl86
 2 years ago
Best ResponseYou've already chosen the best response.0so its factored out then simplfied down?

precal
 2 years ago
Best ResponseYou've already chosen the best response.1once you factor it, then we have a theorem that states we can set them to zero and solve each one

zhengcl86
 2 years ago
Best ResponseYou've already chosen the best response.0when the 4x is factored out the 8x 3rd power becomes 2x 2nd power?

zhengcl86
 2 years ago
Best ResponseYou've already chosen the best response.0was that divided by the 4x? and expondents substracted?

precal
 2 years ago
Best ResponseYou've already chosen the best response.1not I factored it outdw:1358903718312:dwcheck yourself by distributing it back in
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