Im so freaking confused and stupid help me

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Im so freaking confused and stupid help me

Mathematics
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All of the questions are based off of this word problem: efren leaves home at 9am and walks 4 mph. his bro greg leaves 1/2 hr later and runs 8.5 mph in the same direction as efren. predict the time at which gred will catch up to efren
write an expression for the distance of greg's travels per hour let h stand for time in hours!
write an expression for the distance efren travels per hour plus the distance he will have traveled when greg leaves the house

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if greg runs at a speed of 8.5 mph and he runs for h hours, how far will he run?
i dont know
im really stupid no joke when it comes to math
you're not stupid, you just need more practice
say he ran for 1 hour how far would he get?
8.5 miles?
good, in 2 hours he will go ____ miles
17
how did you get that
8.5 x 2
so in 3 hours, he will run 8.5 x 3 = 25.5 miles so in 4 hours, he will run 8.5 x 4 = 34 miles .... in general... if he runs h hours (some unknown amount of hours), then he will run 8.5 x h or just 8.5h miles
so if d = distance traveled, then d = 8.5h
oh okay so it says write an expression but im confused on how to write one
ok so you'll just write 8.5h
8.5h is the expression d = 8.5h is the equation
what about the other expression i have to write for efren
keep in mind that greg started 1/2 hour later than efren
so you have to account for that
oh & it says plus the distance he wil he will have traveled when greg leaves
let's assume they both start at the same time (9:30 am) if efren walks at 4 mph and he does this for h hours, then he will walk a total of 4h miles
so would it be greg leaving at 9:30??
but this isn't the whole story because efren leaves at 9:00 am instead of 9:30 am so he's got a 1/2 hr head start
okay
but i dont know what the distance formula is either thats one of the questions
so you have to add in the fact that he walked some additional distance in that half hour where he got the head start if he walked 0.5 hours (1/2 hr) at a speed of 4 mph, then he would have walked 4*0.5 = 2 miles
distance formula: distance = rate x time d = r x t d = rt
rate is known as speed
oh yeah i remember that lol
so he walked 2 miles??
yes in that half hour where he got the head start
so he walked 2 miles in the first half hour then he walked an additional 4h miles after 9:30 am
in total, efren walked 2+4h or 4h + 2 miles
so what expression would be for efren plus the distance he would of traveled when greg left
4h + 2
4h is the amount he traveled when greg left 2 is the amount he traveled when greg was still at home
oh i see, sorry ive been up all night doing this and im annoyed and fed up :(
thats ok
to find out when the two will meet, you just set the two expressions equal to one another
8.5h = 4h + 2 and solve for h
so the next question is weird it says write an equation setting the distance expressions in steps 3 and 4 equal
yep you want to find out when the two will walk the same distance (ie find out when/where the two will meet)
could you help me figure that out ill try to do most my self
well you see how i got 8.5h = 4h + 2 right?
yup!
you added the time he waited to the expression
ok great, subtract 4h from both sides 8.5h = 4h + 2 8.5h - 4h = 2 4.5h = 2 what's next?
4.5 = 2 - 2 ?
4.5h is the same as 4.5 x h
how do you undo multiplication
OH! :) I know!! 4.5h/4.5 2/4.5
you divide 2 by 4.5
am i right?
you are correct
so h = ??
2/4.5 = ?
h = 0.4 repeating (so line over the 4)
so that's the rough approximation of how many hours it will take (after 9:30) for the two to meet
and for the two to travel the same distance
convert to minutes to get: 0.444*60 = 26.64 so it will take about 26.64 minutes
thank you very much for helping me i wish i was as smart as you i struggle just to keep my B- average
I'm sure you'll do fine, just keep your head up and keep practicing
thank you jim have a nice day!
you're welcome
you too

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