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gianarpt

  • one year ago

Im so freaking confused and stupid help me

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  1. gianarpt
    • one year ago
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    All of the questions are based off of this word problem: efren leaves home at 9am and walks 4 mph. his bro greg leaves 1/2 hr later and runs 8.5 mph in the same direction as efren. predict the time at which gred will catch up to efren

  2. gianarpt
    • one year ago
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    write an expression for the distance of greg's travels per hour let h stand for time in hours!

  3. gianarpt
    • one year ago
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    write an expression for the distance efren travels per hour plus the distance he will have traveled when greg leaves the house

  4. jim_thompson5910
    • one year ago
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    if greg runs at a speed of 8.5 mph and he runs for h hours, how far will he run?

  5. gianarpt
    • one year ago
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    i dont know

  6. gianarpt
    • one year ago
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    im really stupid no joke when it comes to math

  7. jim_thompson5910
    • one year ago
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    you're not stupid, you just need more practice

  8. jim_thompson5910
    • one year ago
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    say he ran for 1 hour how far would he get?

  9. gianarpt
    • one year ago
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    8.5 miles?

  10. jim_thompson5910
    • one year ago
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    good, in 2 hours he will go ____ miles

  11. gianarpt
    • one year ago
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    17

  12. jim_thompson5910
    • one year ago
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    how did you get that

  13. gianarpt
    • one year ago
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    8.5 x 2

  14. jim_thompson5910
    • one year ago
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    so in 3 hours, he will run 8.5 x 3 = 25.5 miles so in 4 hours, he will run 8.5 x 4 = 34 miles .... in general... if he runs h hours (some unknown amount of hours), then he will run 8.5 x h or just 8.5h miles

  15. jim_thompson5910
    • one year ago
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    so if d = distance traveled, then d = 8.5h

  16. gianarpt
    • one year ago
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    oh okay so it says write an expression but im confused on how to write one

  17. jim_thompson5910
    • one year ago
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    ok so you'll just write 8.5h

  18. jim_thompson5910
    • one year ago
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    8.5h is the expression d = 8.5h is the equation

  19. gianarpt
    • one year ago
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    what about the other expression i have to write for efren

  20. jim_thompson5910
    • one year ago
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    keep in mind that greg started 1/2 hour later than efren

  21. jim_thompson5910
    • one year ago
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    so you have to account for that

  22. gianarpt
    • one year ago
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    oh & it says plus the distance he wil he will have traveled when greg leaves

  23. jim_thompson5910
    • one year ago
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    let's assume they both start at the same time (9:30 am) if efren walks at 4 mph and he does this for h hours, then he will walk a total of 4h miles

  24. gianarpt
    • one year ago
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    so would it be greg leaving at 9:30??

  25. jim_thompson5910
    • one year ago
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    but this isn't the whole story because efren leaves at 9:00 am instead of 9:30 am so he's got a 1/2 hr head start

  26. gianarpt
    • one year ago
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    okay

  27. gianarpt
    • one year ago
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    but i dont know what the distance formula is either thats one of the questions

  28. jim_thompson5910
    • one year ago
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    so you have to add in the fact that he walked some additional distance in that half hour where he got the head start if he walked 0.5 hours (1/2 hr) at a speed of 4 mph, then he would have walked 4*0.5 = 2 miles

  29. jim_thompson5910
    • one year ago
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    distance formula: distance = rate x time d = r x t d = rt

  30. jim_thompson5910
    • one year ago
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    rate is known as speed

  31. gianarpt
    • one year ago
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    oh yeah i remember that lol

  32. gianarpt
    • one year ago
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    so he walked 2 miles??

  33. jim_thompson5910
    • one year ago
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    yes in that half hour where he got the head start

  34. jim_thompson5910
    • one year ago
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    so he walked 2 miles in the first half hour then he walked an additional 4h miles after 9:30 am

  35. jim_thompson5910
    • one year ago
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    in total, efren walked 2+4h or 4h + 2 miles

  36. gianarpt
    • one year ago
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    so what expression would be for efren plus the distance he would of traveled when greg left

  37. jim_thompson5910
    • one year ago
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    4h + 2

  38. jim_thompson5910
    • one year ago
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    4h is the amount he traveled when greg left 2 is the amount he traveled when greg was still at home

  39. gianarpt
    • one year ago
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    oh i see, sorry ive been up all night doing this and im annoyed and fed up :(

  40. jim_thompson5910
    • one year ago
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    thats ok

  41. jim_thompson5910
    • one year ago
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    to find out when the two will meet, you just set the two expressions equal to one another

  42. jim_thompson5910
    • one year ago
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    8.5h = 4h + 2 and solve for h

  43. gianarpt
    • one year ago
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    so the next question is weird it says write an equation setting the distance expressions in steps 3 and 4 equal

  44. jim_thompson5910
    • one year ago
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    yep you want to find out when the two will walk the same distance (ie find out when/where the two will meet)

  45. gianarpt
    • one year ago
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    could you help me figure that out ill try to do most my self

  46. jim_thompson5910
    • one year ago
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    well you see how i got 8.5h = 4h + 2 right?

  47. gianarpt
    • one year ago
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    yup!

  48. gianarpt
    • one year ago
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    you added the time he waited to the expression

  49. jim_thompson5910
    • one year ago
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    ok great, subtract 4h from both sides 8.5h = 4h + 2 8.5h - 4h = 2 4.5h = 2 what's next?

  50. gianarpt
    • one year ago
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    4.5 = 2 - 2 ?

  51. jim_thompson5910
    • one year ago
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    4.5h is the same as 4.5 x h

  52. jim_thompson5910
    • one year ago
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    how do you undo multiplication

  53. gianarpt
    • one year ago
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    OH! :) I know!! 4.5h/4.5 2/4.5

  54. gianarpt
    • one year ago
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    you divide 2 by 4.5

  55. gianarpt
    • one year ago
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    am i right?

  56. jim_thompson5910
    • one year ago
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    you are correct

  57. jim_thompson5910
    • one year ago
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    so h = ??

  58. jim_thompson5910
    • one year ago
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    2/4.5 = ?

  59. gianarpt
    • one year ago
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    h = 0.4 repeating (so line over the 4)

  60. jim_thompson5910
    • one year ago
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    so that's the rough approximation of how many hours it will take (after 9:30) for the two to meet

  61. jim_thompson5910
    • one year ago
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    and for the two to travel the same distance

  62. jim_thompson5910
    • one year ago
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    convert to minutes to get: 0.444*60 = 26.64 so it will take about 26.64 minutes

  63. gianarpt
    • one year ago
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    thank you very much for helping me i wish i was as smart as you i struggle just to keep my B- average

  64. jim_thompson5910
    • one year ago
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    I'm sure you'll do fine, just keep your head up and keep practicing

  65. gianarpt
    • one year ago
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    thank you jim have a nice day!

  66. jim_thompson5910
    • one year ago
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    you're welcome

  67. jim_thompson5910
    • one year ago
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    you too

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