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Rick can mop the floor in 5 minutes. Together Rick and Nancy can mop the floor in just 4 minutes. How long would it take Nancy to mop the floor alone?

Mathematics
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ricky's rate is \(\frac{1}{5}\) i.e. he can do one fifth of the job in 5 minutes you want nancy's rate, lets call it \(r\) then you know that \(4(\frac{1}{5}+r)=1\)
you get \[\frac{1}{5}+r=\frac{1}{4}\] \[r=\frac{1}{4}-\frac{1}{5}\]\[r=\frac{1}{20}\]
6 minutes for rick, rick+nancy = 4. Nancy can do it in 2. that way 6 and 2 average to 4.

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Other answers:

so nancy's rate is \(\frac{1}{20}\) of the job in one hour, would take nancy 20 hours working alone
Yeah basically I summed it up but satellite73 has the more detailed answer if yours needed to be in fraction form :)
the answer is not 2, and 4 is not the arithmetic average
in fact that answer is clearly wrong, since if nancy can do it in two hours, how in the world will it take four hours for them to do it together??
So what's the answer?
20 hours working alone? it seems like they want minutes... or do I just convert it to minutes?
like multiplied 60?

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