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dumbsearch2 Group Title

Rick can mop the floor in 5 minutes. Together Rick and Nancy can mop the floor in just 4 minutes. How long would it take Nancy to mop the floor alone?

  • one year ago
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  1. satellite73 Group Title
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    ricky's rate is \(\frac{1}{5}\) i.e. he can do one fifth of the job in 5 minutes you want nancy's rate, lets call it \(r\) then you know that \(4(\frac{1}{5}+r)=1\)

    • one year ago
  2. satellite73 Group Title
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    you get \[\frac{1}{5}+r=\frac{1}{4}\] \[r=\frac{1}{4}-\frac{1}{5}\]\[r=\frac{1}{20}\]

    • one year ago
  3. gianarpt Group Title
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    6 minutes for rick, rick+nancy = 4. Nancy can do it in 2. that way 6 and 2 average to 4.

    • one year ago
  4. satellite73 Group Title
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    so nancy's rate is \(\frac{1}{20}\) of the job in one hour, would take nancy 20 hours working alone

    • one year ago
  5. gianarpt Group Title
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    Yeah basically I summed it up but satellite73 has the more detailed answer if yours needed to be in fraction form :)

    • one year ago
  6. satellite73 Group Title
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    the answer is not 2, and 4 is not the arithmetic average

    • one year ago
  7. satellite73 Group Title
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    in fact that answer is clearly wrong, since if nancy can do it in two hours, how in the world will it take four hours for them to do it together??

    • one year ago
  8. dumbsearch2 Group Title
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    So what's the answer?

    • one year ago
  9. dumbsearch2 Group Title
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    20 hours working alone? it seems like they want minutes... or do I just convert it to minutes?

    • one year ago
  10. dumbsearch2 Group Title
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    like multiplied 60?

    • one year ago
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