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Grazes
Given that f(x)=2x+3 and g(x)=x^2-x+3, determine the value(s) of x such that (f o g)(x)= (g o f)(x). I got 14/(y^2-49) for this, but could someone check for me, please? Thank you!
I don't think you should have any "y"s in your final solution. To solve it, you need to set \[2[x^2-x+3]+3=[2x+3]^2-[2x+3]+3\]and solve for \(x\). Does this make sense?
oh wait. I copied down the answer for a different problem. Would it be x=0, x=-3?
I have 0 as correct, but not -3.