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mariomintchev
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a student signs up for 3 courses for this semester. the probability of getting an a in class 1 is 0.3. the probability of getting an a in class 2 is 0.4. the probability of getting an a in class 3 is 0.5.
 one year ago
 one year ago
mariomintchev Group Title
a student signs up for 3 courses for this semester. the probability of getting an a in class 1 is 0.3. the probability of getting an a in class 2 is 0.4. the probability of getting an a in class 3 is 0.5.
 one year ago
 one year ago

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mariomintchev Group TitleBest ResponseYou've already chosen the best response.0
a) what is the probability of getting 3 As this semester? b) what is the probability of getting 2 As this semester? c) what is the probability of getting at least 1 A this semester?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
a) multiply the three numbers together \(.3\times .4\times .5\) assuming independence
 one year ago

mariomintchev Group TitleBest ResponseYou've already chosen the best response.0
yeah i was thinking the same thing for A but what about the others
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
b) two A's you have to work by cases
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
class 1, class 2, class 3 A A not A \(.3\times .4\times .5\) A not A A \(.3\times .6\times .5\) not A A A \(.7\times .4\times .5\) find these three numbers, add them up
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
c) at least on A is easiest found by computing the probability that you get exactly no A and subtract that number from 1
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
*one A
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
i.e. \(1.7\times .6\times .5\)
 one year ago

mariomintchev Group TitleBest ResponseYou've already chosen the best response.0
Thanks big time!
 one year ago
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