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1. What is the first step in solving g3/7 >5?(Points : 1)
Add 3 to each side.
Subtract 3 from each side.
Divide each side by 7.
Multiply each side by 7.
2. Write an inequality to represent the problem (1 pt.) and then solve the inequality by writing the pairs which solve it (1 pt.).
Find all sets of two consecutive positive odd integers whose sum is less than or equal to 18.
(Points : 2)
 one year ago
 one year ago
1. What is the first step in solving g3/7 >5?(Points : 1) Add 3 to each side. Subtract 3 from each side. Divide each side by 7. Multiply each side by 7. 2. Write an inequality to represent the problem (1 pt.) and then solve the inequality by writing the pairs which solve it (1 pt.). Find all sets of two consecutive positive odd integers whose sum is less than or equal to 18. (Points : 2)
 one year ago
 one year ago

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satellite73Best ResponseYou've already chosen the best response.0
is it \(\frac{g3}{7}>5\) ?
 one year ago

apple_piBest ResponseYou've already chosen the best response.0
Get rid of fractions immediately. ie Multiply by 7. Always your best option
 one year ago

apple_piBest ResponseYou've already chosen the best response.0
@satellite73 It doesn't really matter anyway. It's a fraction so you should multiply by 7.
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
actually try \(n+n+2\leq 18\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
this tell you \(2n+2\leq 18\) \[2n\leq 16\] \[n\leq 8\]so you don't have too many pairs of odd integers to write
 one year ago

apple_piBest ResponseYou've already chosen the best response.0
You should probably set a lower bound: 0 \[0 < n + (n + 2) \le 18\]\[n \in \mathbb{Z}\]
 one year ago
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