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- anonymous

1. What is the first step in solving g-3/7 >5?(Points : 1)
Add 3 to each side.
Subtract 3 from each side.
Divide each side by 7.
Multiply each side by 7.
2. Write an inequality to represent the problem (1 pt.) and then solve the inequality by writing the pairs which solve it (1 pt.).
Find all sets of two consecutive positive odd integers whose sum is less than or equal to 18.
(Points : 2)

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- anonymous

- schrodinger

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- anonymous

is it \(\frac{g-3}{7}>5\) ?

- anonymous

Get rid of fractions immediately. ie Multiply by 7. Always your best option

- anonymous

hello!!

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- anonymous

@satellite73 It doesn't really matter anyway. It's a fraction so you should multiply by 7.

- anonymous

good point

- anonymous

actually try \(n+n+2\leq 18\)

- anonymous

this tell you \(2n+2\leq 18\)
\[2n\leq 16\]
\[n\leq 8\]so you don't have too many pairs of odd integers to write

- anonymous

You should probably set a lower bound: 0
\[0 < n + (n + 2) \le 18\]\[n \in \mathbb{Z}\]

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