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anonymous
 3 years ago
1. What is the first step in solving g3/7 >5?(Points : 1)
Add 3 to each side.
Subtract 3 from each side.
Divide each side by 7.
Multiply each side by 7.
2. Write an inequality to represent the problem (1 pt.) and then solve the inequality by writing the pairs which solve it (1 pt.).
Find all sets of two consecutive positive odd integers whose sum is less than or equal to 18.
(Points : 2)
anonymous
 3 years ago
1. What is the first step in solving g3/7 >5?(Points : 1) Add 3 to each side. Subtract 3 from each side. Divide each side by 7. Multiply each side by 7. 2. Write an inequality to represent the problem (1 pt.) and then solve the inequality by writing the pairs which solve it (1 pt.). Find all sets of two consecutive positive odd integers whose sum is less than or equal to 18. (Points : 2)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is it \(\frac{g3}{7}>5\) ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Get rid of fractions immediately. ie Multiply by 7. Always your best option

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@satellite73 It doesn't really matter anyway. It's a fraction so you should multiply by 7.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0actually try \(n+n+2\leq 18\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this tell you \(2n+2\leq 18\) \[2n\leq 16\] \[n\leq 8\]so you don't have too many pairs of odd integers to write

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You should probably set a lower bound: 0 \[0 < n + (n + 2) \le 18\]\[n \in \mathbb{Z}\]
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