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Emily778

If mB = mD = 39°, find mC so that quadrilateral ABCD is a parallelogram. The diagram is not to scale. (1 point) 39° 282° 141° 78°

  • one year ago
  • one year ago

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  1. Emily778
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    • one year ago
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  2. jim_thompson5910
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    m < C + m < D = 180 x + 39 = 180 solve for x

    • one year ago
  3. Emily778
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    would it be C? (141)

    • one year ago
  4. jim_thompson5910
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    yep

    • one year ago
  5. Emily778
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    Thankyou.

    • one year ago
  6. jim_thompson5910
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    ironic how angle C matches with choice C, but yeah it's correct

    • one year ago
  7. Emily778
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    Based on the information given, can you determine that the quadrilateral must be a parallelogram? Explain. Given: XY congruent to WZ and XW congruent to YZ (1 point) Yes; opposite sides are congruent. Yes; diagonals of a parallelogram bisect each other. Yes; two opposite sides are both parallel and congruent. No; you cannot determine that the quadrilateral is a parallelogram.

    • one year ago
  8. Emily778
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    Can you help me with this one ?

    • one year ago
  9. jim_thompson5910
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    Draw a picture |dw:1358922647384:dw|

    • one year ago
  10. jim_thompson5910
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    XY = WZ (given) XW = YZ (given) opposite sides are congruent, so we definitely have a parellelogram

    • one year ago
  11. Emily778
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    would it be a?

    • one year ago
  12. jim_thompson5910
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    yep

    • one year ago
  13. Emily778
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    wait, are you sure it's not c?

    • one year ago
  14. Emily778
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    can you help me with this? mR = 130 and mS = 80. Find mT. The diagram is not to scale. (1 point) 65 70 35 80

    • one year ago
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  15. Emily778
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    Hello?

    • one year ago
  16. jim_thompson5910
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    no it wouldn't be c because we can't determine the two opposite sides are parallel (yet)

    • one year ago
  17. jim_thompson5910
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    the only thing we are given is that the opposite sides are congruent

    • one year ago
  18. jim_thompson5910
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    Draw a line down the middle like this |dw:1358923282188:dw|

    • one year ago
  19. Emily778
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    ok

    • one year ago
  20. jim_thompson5910
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    then fill in what you know |dw:1358923381801:dw| Note: segment RT is a angle bisector of angle SRU, so angle SRT is half of angle SRU (130/2 = 65)

    • one year ago
  21. jim_thompson5910
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    solve for x, then double the value of x to get the angle T

    • one year ago
  22. Emily778
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    how do I solve for x for this?

    • one year ago
  23. jim_thompson5910
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    if you're not sure how to get x, add up all the angles and they should result in 180 degrees so x+65+80 = 180

    • one year ago
  24. Emily778
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    is it c?

    • one year ago
  25. jim_thompson5910
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    close, but you have to double it

    • one year ago
  26. jim_thompson5910
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    |dw:1358923649111:dw|

    • one year ago
  27. jim_thompson5910
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    |dw:1358923661794:dw|

    • one year ago
  28. Emily778
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    oh, thankyou. Can you help me with 2 more? Or no?

    • one year ago
  29. jim_thompson5910
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    sure i can help

    • one year ago
  30. Emily778
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    In the coordinate plane, three vertices of rectangle HIJK are H(0, 0), I(0, d), and K(e, 0). What are the coordinates of point J? (1 point) (2e, 2d) (d, e) (e, d) And the picture is the last answer

    • one year ago
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  31. jim_thompson5910
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    draw a pic |dw:1358923988803:dw|

    • one year ago
  32. jim_thompson5910
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    do you see what point that last point (? , ?) should be

    • one year ago
  33. Emily778
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    I don't get the answers shown..

    • one year ago
  34. jim_thompson5910
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    what is the x coordinate of this point here |dw:1358924165773:dw|

    • one year ago
  35. Emily778
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    E?

    • one year ago
  36. jim_thompson5910
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    and what is the y coordinate of this point here |dw:1358924211028:dw|

    • one year ago
  37. jim_thompson5910
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    any ideas?

    • one year ago
  38. Emily778
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    is it c? :)

    • one year ago
  39. jim_thompson5910
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    yep the answer is (e, d)

    • one year ago
  40. jim_thompson5910
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    |dw:1358924527223:dw|

    • one year ago
  41. Emily778
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    THANK YOU

    • one year ago
  42. jim_thompson5910
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    you're welcome

    • one year ago
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