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LevB4Lev

  • 3 years ago

(4x+1)^2=20 solve each equation by the square root property

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  1. hartnn
    • 3 years ago
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    did you take square root on both sides, first ? what you get ?

  2. LevB4Lev
    • 3 years ago
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    solve for X i mean

  3. hartnn
    • 3 years ago
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    yeah, take square root on both sides of \((4x+1)^2=20\) what do you get ?

  4. LevB4Lev
    • 3 years ago
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    not sure

  5. LevB4Lev
    • 3 years ago
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    4x-1=\[\sqrt{20}\] =

  6. hartnn
    • 3 years ago
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    that would be \(4x+1 =\pm \sqrt {20}\) ok? now subtract 1 from both sides, what u get ?

  7. LevB4Lev
    • 3 years ago
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    4x=\[\pm \sqrt{20}\] - 1

  8. hartnn
    • 3 years ago
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    thats correct, now just divide both sides by 4 and you get 2 values of x.

  9. LevB4Lev
    • 3 years ago
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    i got x = PM square root 4

  10. hartnn
    • 3 years ago
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    ? how ? \(4x=\pm \sqrt{20}-1 \implies x = \dfrac{\pm \sqrt{20}-1}{4}\)

  11. LevB4Lev
    • 3 years ago
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    |dw:1358934890536:dw|

  12. LevB4Lev
    • 3 years ago
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    so is it 19 divided by 4

  13. hartnn
    • 3 years ago
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    no, it'll only be \( x = \dfrac{\pm \sqrt{20}-1}{4}\) or one simplification will be \( x = \dfrac{\pm 2\sqrt{5}-1}{4}\)

  14. LevB4Lev
    • 3 years ago
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    interesting

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