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LevB4Lev Group Title

(4x+1)^2=20 solve each equation by the square root property

  • one year ago
  • one year ago

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  1. hartnn Group Title
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    did you take square root on both sides, first ? what you get ?

    • one year ago
  2. LevB4Lev Group Title
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    solve for X i mean

    • one year ago
  3. hartnn Group Title
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    yeah, take square root on both sides of \((4x+1)^2=20\) what do you get ?

    • one year ago
  4. LevB4Lev Group Title
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    not sure

    • one year ago
  5. LevB4Lev Group Title
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    4x-1=\[\sqrt{20}\] =

    • one year ago
  6. hartnn Group Title
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    that would be \(4x+1 =\pm \sqrt {20}\) ok? now subtract 1 from both sides, what u get ?

    • one year ago
  7. LevB4Lev Group Title
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    4x=\[\pm \sqrt{20}\] - 1

    • one year ago
  8. hartnn Group Title
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    thats correct, now just divide both sides by 4 and you get 2 values of x.

    • one year ago
  9. LevB4Lev Group Title
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    i got x = PM square root 4

    • one year ago
  10. hartnn Group Title
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    ? how ? \(4x=\pm \sqrt{20}-1 \implies x = \dfrac{\pm \sqrt{20}-1}{4}\)

    • one year ago
  11. LevB4Lev Group Title
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    |dw:1358934890536:dw|

    • one year ago
  12. LevB4Lev Group Title
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    so is it 19 divided by 4

    • one year ago
  13. hartnn Group Title
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    no, it'll only be \( x = \dfrac{\pm \sqrt{20}-1}{4}\) or one simplification will be \( x = \dfrac{\pm 2\sqrt{5}-1}{4}\)

    • one year ago
  14. LevB4Lev Group Title
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    interesting

    • one year ago
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