LevB4Lev
(4x+1)^2=20 solve each equation by the square root property



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hartnn
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did you take square root on both sides, first ? what you get ?

LevB4Lev
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solve for X i mean

hartnn
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yeah, take square root on both sides of \((4x+1)^2=20\)
what do you get ?

LevB4Lev
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not sure

LevB4Lev
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4x1=\[\sqrt{20}\] =

hartnn
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that would be \(4x+1 =\pm \sqrt {20}\)
ok?
now subtract 1 from both sides, what u get ?

LevB4Lev
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4x=\[\pm \sqrt{20}\]  1

hartnn
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thats correct, now just divide both sides by 4 and you get 2 values of x.

LevB4Lev
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i got x = PM square root 4

hartnn
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? how ?
\(4x=\pm \sqrt{20}1 \implies x = \dfrac{\pm \sqrt{20}1}{4}\)

LevB4Lev
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dw:1358934890536:dw

LevB4Lev
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so is it 19 divided by 4

hartnn
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no, it'll only be \( x = \dfrac{\pm \sqrt{20}1}{4}\)
or one simplification will be
\( x = \dfrac{\pm 2\sqrt{5}1}{4}\)

LevB4Lev
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interesting