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LevB4Lev
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(4x+1)^2=20 solve each equation by the square root property
 one year ago
 one year ago
LevB4Lev Group Title
(4x+1)^2=20 solve each equation by the square root property
 one year ago
 one year ago

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hartnn Group TitleBest ResponseYou've already chosen the best response.0
did you take square root on both sides, first ? what you get ?
 one year ago

LevB4Lev Group TitleBest ResponseYou've already chosen the best response.0
solve for X i mean
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
yeah, take square root on both sides of \((4x+1)^2=20\) what do you get ?
 one year ago

LevB4Lev Group TitleBest ResponseYou've already chosen the best response.0
4x1=\[\sqrt{20}\] =
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
that would be \(4x+1 =\pm \sqrt {20}\) ok? now subtract 1 from both sides, what u get ?
 one year ago

LevB4Lev Group TitleBest ResponseYou've already chosen the best response.0
4x=\[\pm \sqrt{20}\]  1
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
thats correct, now just divide both sides by 4 and you get 2 values of x.
 one year ago

LevB4Lev Group TitleBest ResponseYou've already chosen the best response.0
i got x = PM square root 4
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
? how ? \(4x=\pm \sqrt{20}1 \implies x = \dfrac{\pm \sqrt{20}1}{4}\)
 one year ago

LevB4Lev Group TitleBest ResponseYou've already chosen the best response.0
dw:1358934890536:dw
 one year ago

LevB4Lev Group TitleBest ResponseYou've already chosen the best response.0
so is it 19 divided by 4
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
no, it'll only be \( x = \dfrac{\pm \sqrt{20}1}{4}\) or one simplification will be \( x = \dfrac{\pm 2\sqrt{5}1}{4}\)
 one year ago

LevB4Lev Group TitleBest ResponseYou've already chosen the best response.0
interesting
 one year ago
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