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mathew0135

  • 3 years ago

I know this limit should be zero but i'm not sure why. \[\lim_{n \rightarrow \infty} \frac{ 917^(n+100) }{ 955^n }\]

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  1. mathew0135
    • 3 years ago
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    Just to clarify that is 917^(n+100) on the top

  2. trevorivanich
    • 3 years ago
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    Just going to throw a joke out here because it's 4:04am... "The limit does not exist!" - Mean Girls

  3. trevorivanich
    • 3 years ago
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    That's not really the answer though :P

  4. ash2326
    • 3 years ago
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    \[\frac{917^{n+100}}{955^{n}\] \[n-> \infty\] \[{\frac{917}{955}}^n \times 917^100\] \[n\to \infty\] so \[{\frac{917}{955} }^n->0\] \[0\times 917^100=0\]

  5. ash2326
    • 3 years ago
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    oops \[0\times 917^{100}=0\]

  6. mathew0135
    • 3 years ago
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    Think i've got it, how i worked it out was like this. Could be completely wrong but oh well. \[\frac{ n(\frac{ 917^{n+100} }{ n }) }{ 955 }\] \[\frac{ 0 }{ 955 }= 0\] ?

  7. mathew0135
    • 3 years ago
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    wait, left something out.

  8. mathew0135
    • 3 years ago
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    ahhh, just imagine the bottom line as n(955)

  9. ash2326
    • 3 years ago
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    But this part \[\frac{917^{n+100}}{n}\ne 0\] It's of the form \[\frac{\infty}{\infty}\]

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