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ParthKohliBest ResponseYou've already chosen the best response.1
Notice:\[64 ^{4  x} = (4^3)^{4  x}\]
 one year ago

vivalakodaBest ResponseYou've already chosen the best response.0
Oh, 4^3 is equal to 64. So would I make it: \[64^{4x}=64^{4x}\]
 one year ago

lacypennelllBest ResponseYou've already chosen the best response.0
:\ So look in your text book yet?
 one year ago

vivalakodaBest ResponseYou've already chosen the best response.0
Sadly I don't have a textbook, I do online school. I've been trying to reach my teacher all morning but she hasn't responded :/
 one year ago

lacypennelllBest ResponseYou've already chosen the best response.0
I do online school to I know how it feels when a teacher doesn't reach you back ==
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
do what @ParthKohli said rewrite \(64\) as \(4^3\) this means \(64^{4x}=4^{3(4x)}=4^{123x}\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
then you know \(123x=2x\) so you can solve for \(x\)
 one year ago

precalBest ResponseYou've already chosen the best response.0
do what satellite73 tells you to do if you can create the same bases then you can set the exponents equal to each other and solve for x
 one year ago

vivalakodaBest ResponseYou've already chosen the best response.0
Thank you everyone for the help, I understand the problem now.
 one year ago
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