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anonymous
 3 years ago
Find the solution to the equation 64^(4 – x) = 4^(2x)?
anonymous
 3 years ago
Find the solution to the equation 64^(4 – x) = 4^(2x)?

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ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.1Notice:\[64 ^{4  x} = (4^3)^{4  x}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, 4^3 is equal to 64. So would I make it: \[64^{4x}=64^{4x}\]

lacypennelll
 3 years ago
Best ResponseYou've already chosen the best response.0:\ So look in your text book yet?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sadly I don't have a textbook, I do online school. I've been trying to reach my teacher all morning but she hasn't responded :/

lacypennelll
 3 years ago
Best ResponseYou've already chosen the best response.0I do online school to I know how it feels when a teacher doesn't reach you back ==

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do what @ParthKohli said rewrite \(64\) as \(4^3\) this means \(64^{4x}=4^{3(4x)}=4^{123x}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then you know \(123x=2x\) so you can solve for \(x\)

precal
 3 years ago
Best ResponseYou've already chosen the best response.0do what satellite73 tells you to do if you can create the same bases then you can set the exponents equal to each other and solve for x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you everyone for the help, I understand the problem now.
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