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vivalakoda
Group Title
Find the solution to the equation 64^(4 – x) = 4^(2x)?
 one year ago
 one year ago
vivalakoda Group Title
Find the solution to the equation 64^(4 – x) = 4^(2x)?
 one year ago
 one year ago

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ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Notice:\[64 ^{4  x} = (4^3)^{4  x}\]
 one year ago

vivalakoda Group TitleBest ResponseYou've already chosen the best response.0
Oh, 4^3 is equal to 64. So would I make it: \[64^{4x}=64^{4x}\]
 one year ago

lacypennelll Group TitleBest ResponseYou've already chosen the best response.0
:\ So look in your text book yet?
 one year ago

vivalakoda Group TitleBest ResponseYou've already chosen the best response.0
Sadly I don't have a textbook, I do online school. I've been trying to reach my teacher all morning but she hasn't responded :/
 one year ago

lacypennelll Group TitleBest ResponseYou've already chosen the best response.0
I do online school to I know how it feels when a teacher doesn't reach you back ==
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
do what @ParthKohli said rewrite \(64\) as \(4^3\) this means \(64^{4x}=4^{3(4x)}=4^{123x}\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
then you know \(123x=2x\) so you can solve for \(x\)
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
do what satellite73 tells you to do if you can create the same bases then you can set the exponents equal to each other and solve for x
 one year ago

vivalakoda Group TitleBest ResponseYou've already chosen the best response.0
Thank you everyone for the help, I understand the problem now.
 one year ago
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