Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Find the solution to the equation 64^(4 – x) = 4^(2x)?

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

Notice:\[64 ^{4 - x} = (4^3)^{4 - x}\]
Oh, 4^3 is equal to 64. So would I make it: \[64^{4-x}=64^{4-x}\]
:\ So look in your text book yet?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Sadly I don't have a textbook, I do online school. I've been trying to reach my teacher all morning but she hasn't responded :/
I do online school to I know how it feels when a teacher doesn't reach you back =-=
do what @ParthKohli said rewrite \(64\) as \(4^3\) this means \(64^{4-x}=4^{3(4-x)}=4^{12-3x}\)
then you know \(12-3x=2x\) so you can solve for \(x\)
do what satellite73 tells you to do if you can create the same bases then you can set the exponents equal to each other and solve for x
Thank you everyone for the help, I understand the problem now.

Not the answer you are looking for?

Search for more explanations.

Ask your own question