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Notice:\[64 ^{4 - x} = (4^3)^{4 - x}\]

Oh, 4^3 is equal to 64.
So would I make it: \[64^{4-x}=64^{4-x}\]

:\ So look in your text book yet?

I do online school to I know how it feels when a teacher doesn't reach you back =-=

do what @ParthKohli said
rewrite \(64\) as \(4^3\)
this means \(64^{4-x}=4^{3(4-x)}=4^{12-3x}\)

then you know \(12-3x=2x\) so you can solve for \(x\)

Thank you everyone for the help, I understand the problem now.

yw