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Solve the compound inequality 3x + 4 > 5 and x – 2 < 7. Clearly show and explain each step please:)

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Solve the inequality \(3x + 4 > 5 \) to start with.
I have this so far but I don't know how to explain where I combine them. First we start by solving 3x + 4 > 5. 3x + 4 > 5 We subtract 4 from each side. 3x + 4 (-4) > 5 (-4) From here we get: 3x > 1 Now we divide 3 by each side. 3x/3 > 1/3 and we get: x > 1/3 Now we solve for x – 2 < 7. x – 2 < 7 We start by adding 2 to each side x – 2 (+2) < 7 (+2) And from here we get: x < 9

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Here's how you combine: For example, \(x > 1\) and \(9 > x\). Then \(9>x>1\)
Oh okay. Also, if most of the other solutions in my assignment finish with a solution looking like this? (for example) {x | x > -20} with the x | ??

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