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gorica

  • one year ago

Can someone explain me this lim g(t)=0 when g(t)= 1/2s when -s<t<s and 0 otherwise, s goes to 0+ and t is not 0

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  1. SGREBORN
    • one year ago
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    limit of g(t) = 0, is limit of function g for t is near 0. Then g(t) will give a result of 1/2s. This 1/2s, can be measured from positive to the negative, where there is t within the inequality -s<t<s. If there are two possibility +/-, but the main possibility is that S goes towards negative, t will be 0. But if S goes towards positive, t will not be 0.

  2. gorica
    • one year ago
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    why doesn't that limit go to infinity if s goes to 0+?

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