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In the diagram below, is an altitude of ABD. What is the length of ? If necessary, round your answer to two decimal places.
(Picture below.)
 one year ago
 one year ago
PLSPLSPLSPLS HELP. In the diagram below, is an altitude of ABD. What is the length of ? If necessary, round your answer to two decimal places. (Picture below.)
 one year ago
 one year ago

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ZeHanzBest ResponseYou've already chosen the best response.1
First try to prove triangle ACB and ABD are similar. Similar triangles have proportional sides (meaning sides in the big triangle are a constant factor times the sides in the small one). Further hint: you may need the Pythagorean Theorem as well...
 one year ago

marcoduuuhBest ResponseYou've already chosen the best response.0
a^2+b^2=c^2. Where do I input 16 and 30?
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.1
a and b are the rectagular sides, c is the hypothenuse
 one year ago

marcoduuuhBest ResponseYou've already chosen the best response.0
16^2+b^2=30^2 B= 25.38?
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.1
No, a and b are the rectangular sides. In triangle ACB these are 16 and 30, so c²=16²+30²=256+900=1156, so c=34.
 one year ago

marcoduuuhBest ResponseYou've already chosen the best response.0
Now what do I do to find CD?
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.1
ACB and ABD are similar, because they both have a right angle, and they have angle A in common. Similar triangles have proportional sides, which means:\[\frac{ AC }{ AB }=\frac{ AB }{ AD }\] (read as: one side in first triangle : same side in other one= same number. Because in the above equation, you know 3 out of four lengths, you can calculate the fourth (AD). Once AD is known, you get CD = AD16.
 one year ago
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