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rishabh.missionBest ResponseYou've already chosen the best response.0
\[\int\limits_{ }^{}( \sqrt \cot + \sqrt tanx).dx\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
not a nice problem
 one year ago

rishabh.missionBest ResponseYou've already chosen the best response.0
ohh then plz solve
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
where did you get the question from?
 one year ago

rishabh.missionBest ResponseYou've already chosen the best response.0
in Sample Paper
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
that dosent tell me anything
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
can you do it again @Mimi_x3 ?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.3
\[\int \sqrt{tanx}+\sqrt{cotx}dx =>\int\frac{sinx+cosx}{\sqrt{sinxcosx}} => \int\frac{sinx+cosx}{\sqrt{sin2x}}\] \(u=sinxcosx\) =>\(du=(sinx+cosx)dx\) \(1sin2x =u^2\) => \(sin2x = (1u^2)\) Therefore, \[ \int\frac{1}{\sqrt{1u^2}}du\]
 one year ago

amoodaryaBest ResponseYou've already chosen the best response.0
arcsin(sinxcosx) +const
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.3
i have a feeling that something is wrong :
 one year ago

youarestupidBest ResponseYou've already chosen the best response.0
I would help if i could, sorry
 one year ago

amoodaryaBest ResponseYou've already chosen the best response.0
arcsin(sinxcosx) +const this is not answer i write it for you to test "85 Mimi_x3" answer but its not true
 one year ago

amoodaryaBest ResponseYou've already chosen the best response.0
this integral has no answer in simple way
 one year ago

amoodaryaBest ResponseYou've already chosen the best response.0
i turn it to complex form but its not easy
 one year ago

amoodaryaBest ResponseYou've already chosen the best response.0
you diffrenciate this sqrt2 arcsin(sinxcosx) i think its correct
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.3
Yeah, i made a minor error; sorry! Happens, when i dont do it on paper lol \(sin2x = 2sinxcosx\) \(sinxcosx = 1/2sin2x \) \[\int\limits\frac{\sin+cosx}{\sqrt{1/2\sin2x}} =>\sqrt{2} \int\limits\frac{sinx+cosx}{\sqrt{\sin2x}} =>\sqrt{2}\int\limits\frac{1}{\sqrt{1u^{2}}} du\]
 one year ago

rishabh.missionBest ResponseYou've already chosen the best response.0
OK but can i solve this in a different method like can i Re write as \[\int\limits_{}^{} \sqrt{ \tan x} (1+\cot x )dx\] and then Put tan x = t², so that sec²x dx = 2t dt Or \[ dx=2t . dt / 1+t ^{4} \]
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
NCERT example if I am recalling correctly eh ?
 one year ago

TusharaBest ResponseYou've already chosen the best response.0
why did u re write it in that form?... it dusnt look right.......... btw, thats a good question, a challenging one
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.3
@rishabh.mission: the solution i gave; is the easiest method to solve this integral.
 one year ago
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