Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

rishabh.mission

  • 3 years ago

Find ?????

  • This Question is Closed
  1. minecraftchick78
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what?

  2. rishabh.mission
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\int\limits_{ }^{}( \sqrt \cot + \sqrt tanx).dx\]

  3. UnkleRhaukus
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    not a nice problem

  4. rishabh.mission
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ohh then plz solve

  5. UnkleRhaukus
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    where did you get the question from?

  6. rishabh.mission
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    in Sample Paper

  7. UnkleRhaukus
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that dosent tell me anything

  8. UnkleRhaukus
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can you do it again @Mimi_x3 ?

  9. Mimi_x3
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 5

    \[\int \sqrt{tanx}+\sqrt{cotx}dx =>\int\frac{sinx+cosx}{\sqrt{sinxcosx}} => \int\frac{sinx+cosx}{\sqrt{sin2x}}\] \(u=sinx-cosx\) =>\(du=(sinx+cosx)dx\) \(1-sin2x =u^2\) => \(sin2x = (1-u^2)\) Therefore, \[ \int\frac{1}{\sqrt{1-u^2}}du\]

  10. amoodarya
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    arcsin(sinx-cosx) +const

  11. Mimi_x3
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 5

    i have a feeling that something is wrong :|

  12. youarestupid
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I would help if i could, sorry

  13. amoodarya
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    arcsin(sinx-cosx) +const this is not answer i write it for you to test "85 Mimi_x3" answer but its not true

  14. amoodarya
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    this integral has no answer in simple way

  15. amoodarya
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i turn it to complex form but its not easy

  16. amoodarya
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you diffrenciate this sqrt2 arcsin(sinx-cosx) i think its correct

  17. Mimi_x3
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 5

    Yeah, i made a minor error; sorry! Happens, when i dont do it on paper lol \(sin2x = 2sinxcosx\) \(sinxcosx = 1/2sin2x \) \[\int\limits\frac{\sin+cosx}{\sqrt{1/2\sin2x}} =>\sqrt{2} \int\limits\frac{sinx+cosx}{\sqrt{\sin2x}} =>\sqrt{2}\int\limits\frac{1}{\sqrt{1-u^{2}}} du\]

  18. rishabh.mission
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    OK but can i solve this in a different method like can i Re write as \[\int\limits_{}^{} \sqrt{ \tan x} (1+\cot x )dx\] and then Put tan x = t², so that sec²x dx = 2t dt Or \[ dx=2t . dt / 1+t ^{4} \]

  19. shubhamsrg
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    NCERT example if I am recalling correctly eh ?

  20. Tushara
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    why did u re write it in that form?... it dusnt look right.......... btw, thats a good question, a challenging one

  21. rishabh.mission
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah it isz

  22. Mimi_x3
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 5

    @rishabh.mission: the solution i gave; is the easiest method to solve this integral.

  23. rishabh.mission
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok thnku

  24. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy