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mlddmlnog

  • 3 years ago

PLEASE HELP. :(

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  1. mlddmlnog
    • 3 years ago
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    |dw:1358980721038:dw|

  2. RadEn
    • 3 years ago
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    int by sub let u=x+1 ---> du = ...

  3. mlddmlnog
    • 3 years ago
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    then du = 1..? i'll try doing it myself, and come back again if i cant get any farther.

  4. RadEn
    • 3 years ago
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    it should du=dx so, it can be int [0,3] (u^1/2) du = ...

  5. mlddmlnog
    • 3 years ago
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    |dw:1358981552574:dw| ?

  6. mlddmlnog
    • 3 years ago
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    oh wait, nevermindd i did something wrong there.

  7. mlddmlnog
    • 3 years ago
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    i got 13/3, but it says that the answer is -1/4...

  8. mlddmlnog
    • 3 years ago
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    oh WAIT. no sorry it says the answer is 14/3.

  9. RadEn
    • 3 years ago
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    do u know, what's the integrate of u^1/2 du ?

  10. mlddmlnog
    • 3 years ago
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    yes. it is \[\frac{ 2u ^{3/2} }{ 3 }\]

  11. RadEn
    • 3 years ago
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    yes, correct.. and after that u have to subtitute back u=(x+1). right ?

  12. mlddmlnog
    • 3 years ago
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    |dw:1358982043647:dw|

  13. RadEn
    • 3 years ago
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    |dw:1358982171324:dw|

  14. mlddmlnog
    • 3 years ago
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    ahh I made a silly mistake. thank you !!! :D

  15. RadEn
    • 3 years ago
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    very welcome ")

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