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heathernelly
 3 years ago
PLEASE HELP!!!
What is the product in simplest form? State any restrictions on the variable.
z^2/z+1 times z^2+3z+2/z^2+3z
heathernelly
 3 years ago
PLEASE HELP!!! What is the product in simplest form? State any restrictions on the variable. z^2/z+1 times z^2+3z+2/z^2+3z

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phi
 3 years ago
Best ResponseYou've already chosen the best response.5can you factor the quadratic ?

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.1can you factor all of it? :S is it (z+2)(z+1)?

phi
 3 years ago
Best ResponseYou've already chosen the best response.5you can check: multiply (z+2)(z+1) = z^2 +2z + z +2 = x^2 +3z+2 yes that works. how about the bottom ?

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.1hm, I'm not sure..

phi
 3 years ago
Best ResponseYou've already chosen the best response.5look for a common factor (hint: z)

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.1i don't know how to factor the bottom half, i'm really bad at factoring

phi
 3 years ago
Best ResponseYou've already chosen the best response.5example: x(x+2) = x^2 +2x or undoing it x^2 +2x =x(x+2)

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.1x(x+3)? i really don't know :/

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.1oh, so i got it right? :D

phi
 3 years ago
Best ResponseYou've already chosen the best response.5yes, except they are using z z(z+3) can be written as z^2 +3z (distribute the z) so yes

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.1well that's easy :) what's next?

phi
 3 years ago
Best ResponseYou've already chosen the best response.5write down what we have after all the factoring , and see what we have

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.1just what we wrote up there? :/

phi
 3 years ago
Best ResponseYou've already chosen the best response.5like this \[ \frac{z\cdot z}{(z+1)} \cdot \frac{(z+2)(z+1) }{z(z+3)} \]

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.1then cross out z+1 and z...which would be z+2 / z+3?

phi
 3 years ago
Best ResponseYou've already chosen the best response.5now you (hopefully) know that when you divide something by itself you get 1, so we an cancel terms that are in both the top and bottom

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.1restriction is that x cannot be 0 or 3?

phi
 3 years ago
Best ResponseYou've already chosen the best response.5yes, but I think there is another z up top. Check your canceling.

phi
 3 years ago
Best ResponseYou've already chosen the best response.5yes, up top we had z^2 or z*z and only 1 z in the bottom

phi
 3 years ago
Best ResponseYou've already chosen the best response.5no 1. You almost have it. \[ \frac{z\cdot z \cdot (z+2)(z+1) }{z(z+3)(z+1)} \]

phi
 3 years ago
Best ResponseYou've already chosen the best response.5and yes, the restricted values are 0, 3, and 1 what do you have for the final answer?

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.1hm, z^2+2z/z+3? :S

phi
 3 years ago
Best ResponseYou've already chosen the best response.5yes, with restrictions that z is not 0, 1 or 3

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.1you are awesome! tytyty :D x

phi
 3 years ago
Best ResponseYou've already chosen the best response.5though I would put parens around it just to be clear. (z^2+2z)/(z+3) and no :S (ha ha)

phi
 3 years ago
Best ResponseYou've already chosen the best response.5Here are some videos http://www.khanacademy.org/math/algebra/rationalexpressions/simplifyingrationalalg/v/simplifyingrationalexpressionsintroduction they are very helpful

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.1haha, you mean yes! thanks :)

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.1i'll check them out! :D
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