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 one year ago
PLEASE HELP!!!
What is the product in simplest form? State any restrictions on the variable.
z^2/z+1 times z^2+3z+2/z^2+3z
 one year ago
PLEASE HELP!!! What is the product in simplest form? State any restrictions on the variable. z^2/z+1 times z^2+3z+2/z^2+3z

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phi
 one year ago
Best ResponseYou've already chosen the best response.4can you factor the quadratic ?

heathernelly
 one year ago
Best ResponseYou've already chosen the best response.1can you factor all of it? :S is it (z+2)(z+1)?

phi
 one year ago
Best ResponseYou've already chosen the best response.4you can check: multiply (z+2)(z+1) = z^2 +2z + z +2 = x^2 +3z+2 yes that works. how about the bottom ?

heathernelly
 one year ago
Best ResponseYou've already chosen the best response.1hm, I'm not sure..

phi
 one year ago
Best ResponseYou've already chosen the best response.4look for a common factor (hint: z)

heathernelly
 one year ago
Best ResponseYou've already chosen the best response.1i don't know how to factor the bottom half, i'm really bad at factoring

phi
 one year ago
Best ResponseYou've already chosen the best response.4example: x(x+2) = x^2 +2x or undoing it x^2 +2x =x(x+2)

heathernelly
 one year ago
Best ResponseYou've already chosen the best response.1x(x+3)? i really don't know :/

heathernelly
 one year ago
Best ResponseYou've already chosen the best response.1oh, so i got it right? :D

phi
 one year ago
Best ResponseYou've already chosen the best response.4yes, except they are using z z(z+3) can be written as z^2 +3z (distribute the z) so yes

phi
 one year ago
Best ResponseYou've already chosen the best response.4so what do we have so far?

heathernelly
 one year ago
Best ResponseYou've already chosen the best response.1well that's easy :) what's next?

phi
 one year ago
Best ResponseYou've already chosen the best response.4write down what we have after all the factoring , and see what we have

heathernelly
 one year ago
Best ResponseYou've already chosen the best response.1just what we wrote up there? :/

phi
 one year ago
Best ResponseYou've already chosen the best response.4like this \[ \frac{z\cdot z}{(z+1)} \cdot \frac{(z+2)(z+1) }{z(z+3)} \]

heathernelly
 one year ago
Best ResponseYou've already chosen the best response.1then cross out z+1 and z...which would be z+2 / z+3?

phi
 one year ago
Best ResponseYou've already chosen the best response.4now you (hopefully) know that when you divide something by itself you get 1, so we an cancel terms that are in both the top and bottom

heathernelly
 one year ago
Best ResponseYou've already chosen the best response.1restriction is that x cannot be 0 or 3?

phi
 one year ago
Best ResponseYou've already chosen the best response.4yes, but I think there is another z up top. Check your canceling.

phi
 one year ago
Best ResponseYou've already chosen the best response.4yes, up top we had z^2 or z*z and only 1 z in the bottom

phi
 one year ago
Best ResponseYou've already chosen the best response.4no 1. You almost have it. \[ \frac{z\cdot z \cdot (z+2)(z+1) }{z(z+3)(z+1)} \]

phi
 one year ago
Best ResponseYou've already chosen the best response.4and yes, the restricted values are 0, 3, and 1 what do you have for the final answer?

heathernelly
 one year ago
Best ResponseYou've already chosen the best response.1hm, z^2+2z/z+3? :S

phi
 one year ago
Best ResponseYou've already chosen the best response.4yes, with restrictions that z is not 0, 1 or 3

heathernelly
 one year ago
Best ResponseYou've already chosen the best response.1you are awesome! tytyty :D x

phi
 one year ago
Best ResponseYou've already chosen the best response.4though I would put parens around it just to be clear. (z^2+2z)/(z+3) and no :S (ha ha)

phi
 one year ago
Best ResponseYou've already chosen the best response.4Here are some videos http://www.khanacademy.org/math/algebra/rationalexpressions/simplifyingrationalalg/v/simplifyingrationalexpressionsintroduction they are very helpful

heathernelly
 one year ago
Best ResponseYou've already chosen the best response.1haha, you mean yes! thanks :)

heathernelly
 one year ago
Best ResponseYou've already chosen the best response.1i'll check them out! :D
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