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can you factor the quadratic ?

can you factor all of it? :S is it (z+2)(z+1)?

hm, I'm not sure..

look for a common factor (hint: z)

i don't know how to factor the bottom half, i'm really bad at factoring

example: x(x+2) = x^2 +2x
or undoing it x^2 +2x =x(x+2)

x(x+3)? i really don't know :/

oh, so i got it right? :D

yes, except they are using z
z(z+3) can be written as z^2 +3z (distribute the z)
so yes

so what do we have so far?

well that's easy :) what's next?

write down what we have after all the factoring , and see what we have

just what we wrote up there? :/

like this
\[ \frac{z\cdot z}{(z+1)} \cdot \frac{(z+2)(z+1) }{z(z+3)} \]

then cross out z+1 and z...which would be z+2 / z+3?

restriction is that x cannot be 0 or -3?

yes, but I think there is another z up top. Check your canceling.

oh

-1?

yes, up top we had z^2 or z*z and only 1 z in the bottom

no -1. You almost have it.
\[ \frac{z\cdot z \cdot (z+2)(z+1) }{z(z+3)(z+1)} \]

and yes, the restricted values are 0, -3, and -1
what do you have for the final answer?

hm, z^2+2z/z+3? :S

yes, with restrictions that z is not 0, -1 or -3

you are awesome! tytyty :D x

though I would put parens around it just to be clear.
(z^2+2z)/(z+3)
and no :S (ha ha)

haha, you mean yes! thanks :)

i'll check them out! :D