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Calculus. Help. :'(

Mathematics
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for what non-negative valuof b is the line given by \[y=-\frac{ 1 }{ 3 }x+b\] perpendicular to the curve y=x^3?
take the derivative (with respect to x) of both equations , what do you get?
i got.. y'=-1/3+b and y'=3x^2 ..

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Other answers:

waht do you do next?
try the derivative of the first equation again ( you made a mistake)
hm... i can't seem to find what my mistake was.. :/ is it the +b part??? because I do not know what to do with that...
b is really bx^0
so then, it would just be y'=-1/3???
thats better
so you have found the first derivatives of the those lines, the first derivative is the slope of the line
the product of the slopes of perpendicular lines is -1
yes.. uhm.. give me a few min to think please :)
sure,
ah, i'm struggling.. please help
ok , so \[m_1\times m_2=-1\] \[m_1=-\frac13\qquad\qquad m_2=3x^2\] solve for x
x=+1 or -1 .
good
now set \[y_1=y_2\] take the first case (x=-1) and find b
does that make sense?
yes it does :) sorry. open study was being so slow .but i get it now. thank you! :)
what did you you get for an answer/
no what do i do..?

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