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anonymous
 3 years ago
Calculus. Help. :'(
anonymous
 3 years ago
Calculus. Help. :'(

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for what nonnegative valuof b is the line given by \[y=\frac{ 1 }{ 3 }x+b\] perpendicular to the curve y=x^3?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1take the derivative (with respect to x) of both equations , what do you get?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got.. y'=1/3+b and y'=3x^2 ..

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1try the derivative of the first equation again ( you made a mistake)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hm... i can't seem to find what my mistake was.. :/ is it the +b part??? because I do not know what to do with that...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so then, it would just be y'=1/3???

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1so you have found the first derivatives of the those lines, the first derivative is the slope of the line

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1the product of the slopes of perpendicular lines is 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes.. uhm.. give me a few min to think please :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ah, i'm struggling.. please help

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1ok , so \[m_1\times m_2=1\] \[m_1=\frac13\qquad\qquad m_2=3x^2\] solve for x

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1now set \[y_1=y_2\] take the first case (x=1) and find b

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1does that make sense?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes it does :) sorry. open study was being so slow .but i get it now. thank you! :)

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1what did you you get for an answer/
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