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mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
for what nonnegative valuof b is the line given by \[y=\frac{ 1 }{ 3 }x+b\] perpendicular to the curve y=x^3?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
take the derivative (with respect to x) of both equations , what do you get?
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
i got.. y'=1/3+b and y'=3x^2 ..
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
waht do you do next?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
try the derivative of the first equation again ( you made a mistake)
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
hm... i can't seem to find what my mistake was.. :/ is it the +b part??? because I do not know what to do with that...
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
b is really bx^0
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
so then, it would just be y'=1/3???
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
thats better
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
so you have found the first derivatives of the those lines, the first derivative is the slope of the line
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
the product of the slopes of perpendicular lines is 1
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
yes.. uhm.. give me a few min to think please :)
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
sure,
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
ah, i'm struggling.. please help
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
ok , so \[m_1\times m_2=1\] \[m_1=\frac13\qquad\qquad m_2=3x^2\] solve for x
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
x=+1 or 1 .
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
now set \[y_1=y_2\] take the first case (x=1) and find b
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
does that make sense?
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
yes it does :) sorry. open study was being so slow .but i get it now. thank you! :)
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
what did you you get for an answer/
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
no what do i do..?
 one year ago
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