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KatClaire

  • 3 years ago

Find the following integral

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  1. kugler97
    • 3 years ago
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    what is the integer?

  2. KatClaire
    • 3 years ago
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    \[\int\limits_{}^{} \frac{ (2t+1)^{2} }{ \sqrt{t} } dt\]

  3. KatClaire
    • 3 years ago
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    does \[\frac{ t ^{2} }{ \sqrt{t} } \] cancel out????

  4. RadEn
    • 3 years ago
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    u need to expand of (2t + 1)^2 = 4t^2 + 4t + 1 and convert sqrt(t) = t^(1/2) now, can u simplify (4t^2 + 4t + 1)/t^(1/2) ?

  5. kugler97
    • 3 years ago
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    yea i think it does lol

  6. KatClaire
    • 3 years ago
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    well I'll show you how far I got \[4 \int\limits_{}^{} \frac{ t ^{2} }{ t ^{1/2} } +4 \int\limits_{}^{} \frac{ t }{ t ^{1/2} } + \int\limits_{}^{} \frac{ 1 }{ t ^{1/2} }\]

  7. RadEn
    • 3 years ago
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    so far is good, then use the properties of exponent to simplify of them : |dw:1358987039172:dw|

  8. RadEn
    • 3 years ago
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    now, what would be ur integral ?

  9. KatClaire
    • 3 years ago
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    Sorry openstudy crapped out last night lol thanks

  10. RadEn
    • 3 years ago
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    nopes.. :) btw, do u got it ?

  11. KatClaire
    • 3 years ago
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    Mhmm :) I got \[\frac{ 8t ^{^{5/2}} }{ 5 }+\frac{ 8t ^{3/2} }{ 3 }+ 2t ^{1/2}+c\] Look about right?

  12. RadEn
    • 3 years ago
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    yeah, i have cheked ur answer you are right :)

  13. KatClaire
    • 3 years ago
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    Hehe you are the best thanks!!!!

  14. RadEn
    • 3 years ago
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    you're welcome

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