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mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
dw:1358986487783:dw
 one year ago

lilfayfay Group TitleBest ResponseYou've already chosen the best response.0
so you need to find the antiderivative correct?
 one year ago

lilfayfay Group TitleBest ResponseYou've already chosen the best response.0
hmm are u guys doing Integration rite now? haha xD
 one year ago

lilfayfay Group TitleBest ResponseYou've already chosen the best response.0
cause im taking Calculus atm :)
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
oh, no our exam is tom.. so i'm doing the review sheet and I have no idea how to do this... :/
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
@UnkleRhaukus help? :'(
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
@zepdrix help??? :'(
 one year ago

lilfayfay Group TitleBest ResponseYou've already chosen the best response.0
hm sorry it looked easy for a minute but idk what to do with the x
 one year ago

lilfayfay Group TitleBest ResponseYou've already chosen the best response.0
sorry.. :\
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Hmmmm I'm not familiar with seeing absolutes in integrals either. I think this is how we would deal with it though. Think about the function \(y=x\). It's a Vshape, formed by 2 lines, \(y=x\) when \(x \lt0\) and \(y=x\) when \(x \gt0\). So I think we can replace the abs(x) with x when our integral is dealing with values of x which are less than 0. And then also replace abs(x) with +x when we're dealing with positive values of x. Let's start by splitting up the integral.\[\large \int\limits_{1}^3 \frac{x}{x}dx \qquad \rightarrow \qquad \int\limits_{1}^0 \frac{x}{x}dx+\int\limits_{0}^3 \frac{x}{x}dx\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Notice that we're dealing with NEGATIVE x's in the boundaries of the first integral, and POSITIVE x's in the boundaries of the second. \[\large \int\limits\limits_{1}^0 \frac{x}{x}dx+\int\limits\limits_{0}^3 \frac{x}{x}dx\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
I think that's what you're suppose to do.... I'm not positive though :3
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
ah thank you zepdrix. haha even though i just gave up on this one. it's too confusing for me.. i will post the next quesiton though. exam's tom :( and open study has been acting really really slowww. i couldnt get on for like an hour.
 one year ago
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