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mlddmlnog

  • 3 years ago

Help , Calculus!

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  1. mlddmlnog
    • 3 years ago
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    The average (mean) of \[\sqrt{x}\] over the interval \[0 \le x \le 2\] is..?

  2. mlddmlnog
    • 3 years ago
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    The answer is given again . it is \[\frac{ 2 }{ 3 }\sqrt{2}\]

  3. zepdrix
    • 3 years ago
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    \[\huge f_{ave}=\frac{1}{b-a}\int\limits_a^b f(x) dx\]

  4. zepdrix
    • 3 years ago
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    \[\huge f_{ave}=\frac{1}{2-0}\int\limits_0^2 x^{1/2}dx\]

  5. zepdrix
    • 3 years ago
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    This one seems pretty easy :D I think you can do it.

  6. mlddmlnog
    • 3 years ago
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    hm.. i'll try :)

  7. mlddmlnog
    • 3 years ago
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    i got... \[\frac{ 2^{\frac{ 3 }{ 2 }} }{ 3 }\] ... :(

  8. zepdrix
    • 3 years ago
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    Yes good :)

  9. zepdrix
    • 3 years ago
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    Make sure you can convert things from rational expressions to roots+powers, otherwise you'll have a tough time identifying when you have the correct answer.

  10. mlddmlnog
    • 3 years ago
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    ahh that's why i kept on thinking that i did it wrong! haha

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