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mlddmlnog
 3 years ago
Help , Calculus!
mlddmlnog
 3 years ago
Help , Calculus!

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mlddmlnog
 3 years ago
Best ResponseYou've already chosen the best response.0The average (mean) of \[\sqrt{x}\] over the interval \[0 \le x \le 2\] is..?

mlddmlnog
 3 years ago
Best ResponseYou've already chosen the best response.0The answer is given again . it is \[\frac{ 2 }{ 3 }\sqrt{2}\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge f_{ave}=\frac{1}{ba}\int\limits_a^b f(x) dx\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge f_{ave}=\frac{1}{20}\int\limits_0^2 x^{1/2}dx\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1This one seems pretty easy :D I think you can do it.

mlddmlnog
 3 years ago
Best ResponseYou've already chosen the best response.0i got... \[\frac{ 2^{\frac{ 3 }{ 2 }} }{ 3 }\] ... :(

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Make sure you can convert things from rational expressions to roots+powers, otherwise you'll have a tough time identifying when you have the correct answer.

mlddmlnog
 3 years ago
Best ResponseYou've already chosen the best response.0ahh that's why i kept on thinking that i did it wrong! haha
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