mlddmlnog
Help , Calculus!
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mlddmlnog
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The average (mean) of \[\sqrt{x}\] over the interval \[0 \le x \le 2\] is..?
mlddmlnog
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The answer is given again . it is \[\frac{ 2 }{ 3 }\sqrt{2}\]
zepdrix
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\[\huge f_{ave}=\frac{1}{b-a}\int\limits_a^b f(x) dx\]
zepdrix
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\[\huge f_{ave}=\frac{1}{2-0}\int\limits_0^2 x^{1/2}dx\]
zepdrix
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This one seems pretty easy :D
I think you can do it.
mlddmlnog
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hm.. i'll try :)
mlddmlnog
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i got... \[\frac{ 2^{\frac{ 3 }{ 2 }} }{ 3 }\] ... :(
zepdrix
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Yes good :)
zepdrix
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Make sure you can convert things from rational expressions to roots+powers, otherwise you'll have a tough time identifying when you have the correct answer.
mlddmlnog
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ahh that's why i kept on thinking that i did it wrong! haha