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mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
The average (mean) of \[\sqrt{x}\] over the interval \[0 \le x \le 2\] is..?
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
The answer is given again . it is \[\frac{ 2 }{ 3 }\sqrt{2}\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\huge f_{ave}=\frac{1}{ba}\int\limits_a^b f(x) dx\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\huge f_{ave}=\frac{1}{20}\int\limits_0^2 x^{1/2}dx\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
This one seems pretty easy :D I think you can do it.
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
hm.. i'll try :)
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
i got... \[\frac{ 2^{\frac{ 3 }{ 2 }} }{ 3 }\] ... :(
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Yes good :)
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Make sure you can convert things from rational expressions to roots+powers, otherwise you'll have a tough time identifying when you have the correct answer.
 one year ago

mlddmlnog Group TitleBest ResponseYou've already chosen the best response.0
ahh that's why i kept on thinking that i did it wrong! haha
 one year ago
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