anonymous
  • anonymous
Help , Calculus!
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
The average (mean) of \[\sqrt{x}\] over the interval \[0 \le x \le 2\] is..?
anonymous
  • anonymous
The answer is given again . it is \[\frac{ 2 }{ 3 }\sqrt{2}\]
zepdrix
  • zepdrix
\[\huge f_{ave}=\frac{1}{b-a}\int\limits_a^b f(x) dx\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

zepdrix
  • zepdrix
\[\huge f_{ave}=\frac{1}{2-0}\int\limits_0^2 x^{1/2}dx\]
zepdrix
  • zepdrix
This one seems pretty easy :D I think you can do it.
anonymous
  • anonymous
hm.. i'll try :)
anonymous
  • anonymous
i got... \[\frac{ 2^{\frac{ 3 }{ 2 }} }{ 3 }\] ... :(
zepdrix
  • zepdrix
Yes good :)
zepdrix
  • zepdrix
Make sure you can convert things from rational expressions to roots+powers, otherwise you'll have a tough time identifying when you have the correct answer.
anonymous
  • anonymous
ahh that's why i kept on thinking that i did it wrong! haha

Looking for something else?

Not the answer you are looking for? Search for more explanations.