anonymous
  • anonymous
Help , Calculus!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
The average (mean) of \[\sqrt{x}\] over the interval \[0 \le x \le 2\] is..?
anonymous
  • anonymous
The answer is given again . it is \[\frac{ 2 }{ 3 }\sqrt{2}\]
zepdrix
  • zepdrix
\[\huge f_{ave}=\frac{1}{b-a}\int\limits_a^b f(x) dx\]

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zepdrix
  • zepdrix
\[\huge f_{ave}=\frac{1}{2-0}\int\limits_0^2 x^{1/2}dx\]
zepdrix
  • zepdrix
This one seems pretty easy :D I think you can do it.
anonymous
  • anonymous
hm.. i'll try :)
anonymous
  • anonymous
i got... \[\frac{ 2^{\frac{ 3 }{ 2 }} }{ 3 }\] ... :(
zepdrix
  • zepdrix
Yes good :)
zepdrix
  • zepdrix
Make sure you can convert things from rational expressions to roots+powers, otherwise you'll have a tough time identifying when you have the correct answer.
anonymous
  • anonymous
ahh that's why i kept on thinking that i did it wrong! haha

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