Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

mlddmlnog Group Title

let f and g be differentiable functions such that f(1)=2 f'(1)=3 f'(2)=-4 g(1)=2 g'(1)=-3 g'(2)=5 if h(x)=f(g(x)), then h'(1)=?

  • one year ago
  • one year ago

  • This Question is Closed
  1. mlddmlnog Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    the answer is 12.

    • one year ago
  2. mlddmlnog Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @zepdrix

    • one year ago
  3. zepdrix Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    So you have to kind of remember the DEFINITION of the chain rule for this one.

    • one year ago
  4. zepdrix Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\large h(x)=f(g(x))\]The chain rule will produce this.\[\large h'(x)=f'(g(x))\cdot g'(x)\]

    • one year ago
  5. mlddmlnog Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    oh.. wait. i'll try to do it myself now. thank you for giving me a start! :)

    • one year ago
  6. mlddmlnog Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yay i got it :)

    • one year ago
  7. zepdrix Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yay

    • one year ago
  8. mlddmlnog Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    here i the next one that's kind of similar to this. but i don't get. If \[f(x)=x ^{3}+3x ^{2}+4x+5\] and g(x)=5, then g(f(x))=?

    • one year ago
  9. zepdrix Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Hmmmmm....

    • one year ago
  10. mlddmlnog Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    The answer is 5.

    • one year ago
  11. zepdrix Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    So here is how a composition of functions works. Everywhere you see an x, you replace it with f(x). Example:\[\large \color{orangered}{f(x)=2x}\]\[\large g(\color{cornflowerblue}{x})=\color{cornflowerblue}{x}+3\] \[\large g(\color{orangered}{f(x)})=\color{orangered}{f(x)}+3\]

    • one year ago
  12. zepdrix Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    In the problem we've been given, the function \(g(x)\) is CONSTANT. There are no x's! So when we plug f(x) into it, it should give us the same answer, because g(x) is always 5. Always constant. You could do the composition thing I explained earlier and it might make sense. If you try to plug in f(x) for any x's in g, you'll see that you have nowhere to actually plug it in.

    • one year ago
  13. zepdrix Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Is your teacher any good? Because so far I'm really really disliking these problems. None of them are straight forward. It just feels like he gave you a list of puzzles to work on.

    • one year ago
  14. mlddmlnog Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    haha yes. she loves these types of questions. -_____- all of her questions are like this. making our brains explode. it literally takes me like 8 hours to do hw. it's insane.

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.