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 2 years ago
The square of x is equal to 4 times the square of y. If x is 1 more than twice y, what is the value of x?
i) 4
ii)  1/2
iii)  1/4
iv) 1/4
v) 1/2
 2 years ago
The square of x is equal to 4 times the square of y. If x is 1 more than twice y, what is the value of x? i) 4 ii)  1/2 iii)  1/4 iv) 1/4 v) 1/2

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Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0\[x^2=4y^2\] \[x=2y+1\] Use substitution.

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.0@amishra try the method suggested above^

amishra
 2 years ago
Best ResponseYou've already chosen the best response.0I tried, but I am not getting the correct answer :

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0Okay...Everytime you see the letter x, substitute this: (2y+1)

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0\[x^2=4y^2\] \[(2y+1)^2=4y^2\]

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0Now you can do it using your knowledge of expanding.

abhrag321
 2 years ago
Best ResponseYou've already chosen the best response.0from the eq. x=2y+1 we get, y=(x1)/2 now x^2=4y^2 =>x^2=4[(x1)/2]^2=4[(x1)^2]/4=(x1)^2=x^22x+1 =>2x1=0 =>x=1/2

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0@abhrag321 Good job going against the Code of Contact of sharing answers and not actually helping them understand the question.

amishra
 2 years ago
Best ResponseYou've already chosen the best response.0Its okay. I finally understood my mistake. I was searching for y instead of x :P THANK YOU SO MUCH FOR YOUR HELP!!!!!!!!!!

abhrag321
 2 years ago
Best ResponseYou've already chosen the best response.0I have read the Code of Conduct. There is the line, "Don't provide someone with just the answer  explain the process, and help guide them through understanding the problem." So please explain the violation process.
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