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The square of x is equal to 4 times the square of y. If x is 1 more than twice y, what is the value of x? i) -4 ii) - 1/2 iii) - 1/4 iv) 1/4 v) 1/2

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\[x^2=4y^2\] \[x=2y+1\] Use substitution.
@amishra try the method suggested above^
I tried, but I am not getting the correct answer :|

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Other answers:

Okay...Everytime you see the letter x, substitute this: (2y+1)
\[x^2=4y^2\] \[(2y+1)^2=4y^2\]
Now you can do it using your knowledge of expanding.
from the eq. x=2y+1 we get, y=(x-1)/2 now x^2=4y^2 =>x^2=4[(x-1)/2]^2=4[(x-1)^2]/4=(x-1)^2=x^2-2x+1 =>2x-1=0 =>x=1/2
@abhrag321 Good job going against the Code of Contact of sharing answers and not actually helping them understand the question.
Code of Conduct*
Its okay. I finally understood my mistake. I was searching for y instead of x :P THANK YOU SO MUCH FOR YOUR HELP!!!!!!!!!!
I have read the Code of Conduct. There is the line, "Don't provide someone with just the answer - explain the process, and help guide them through understanding the problem." So please explain the violation process.

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