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It is chlorination with a single chlorine atom
The results of adding a chlorine to a branched carbon. The chlorine can end up attached to any carbon it wants, but it will not attach to any substituent carbons.
|dw:1359010362588:dw| how many product are formed by monochlorination of above
@str8up4wd @brando1996 @kim2012
I'm assuming this is a radical reaction as that is the only method I ca think of at the top of to add a halogen. As you may already know, radical reactions form MANY products. I would assume for this answer you are looking for the most stable product, which are basically 2º ad 3º. With that being said, How many products do YOU guess. I am going to hint that I see about 7+
I'm going to guess 7, but you can form more products (minor products) where the chlorine attaches as a 1º. Which is why I suggested there are 7+. I would count everywhere where the chlorine forms a secondary or tertiary position.
wat ever u hav writeen i'm nt getting it properly.:(
I don't quite understand you, you say you have not covered this, but you are seeking answers to discuss this with your professor? Just tell him that you think 7 major products because they form 2º position thus making it more stable.
in answer its given 14.
@abb0t can u draw the structure that how 7 is possible.
I told you 7+ that's because you would get a majority of 7 because 2º substituted is more favorable over a 1º!! They got 14 because technically, a chlorine atom can attach everywhere on this structure! Wherever there's a hydrogen, a chlorine can be substituted. Read up on radical reaction and halogen subsitution on alkanes!
You have highlighted 15 positions; Actually, two of them at bottom-left lead to the same compound. So there are only 14 possibilities. |dw:1359014949581:dw|
My bad. Totally missed that. Thanks @Vincent-Lyon.Fr
ch3 here 3 hydogen r present so we count 3 time i.e we can place chlorine 3 time |dw:1359169049356:dw|
I don't understand your question.
the three places are equivalent