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AravindGBest ResponseYou've already chosen the best response.0
It is chlorination with a single chlorine atom
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
The results of adding a chlorine to a branched carbon. The chlorine can end up attached to any carbon it wants, but it will not attach to any substituent carbons.
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
dw:1359010362588:dw how many product are formed by monochlorination of above
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
@str8up4wd @brando1996 @kim2012
 one year ago

abb0tBest ResponseYou've already chosen the best response.1
I'm assuming this is a radical reaction as that is the only method I ca think of at the top of to add a halogen. As you may already know, radical reactions form MANY products. I would assume for this answer you are looking for the most stable product, which are basically 2º ad 3º. With that being said, How many products do YOU guess. I am going to hint that I see about 7+
 one year ago

abb0tBest ResponseYou've already chosen the best response.1
I'm going to guess 7, but you can form more products (minor products) where the chlorine attaches as a 1º. Which is why I suggested there are 7+. I would count everywhere where the chlorine forms a secondary or tertiary position.
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
wat ever u hav writeen i'm nt getting it properly.:(
 one year ago

abb0tBest ResponseYou've already chosen the best response.1
I don't quite understand you, you say you have not covered this, but you are seeking answers to discuss this with your professor? Just tell him that you think 7 major products because they form 2º position thus making it more stable.
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
in answer its given 14.
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
@abb0t can u draw the structure that how 7 is possible.
 one year ago

abb0tBest ResponseYou've already chosen the best response.1
I told you 7+ that's because you would get a majority of 7 because 2º substituted is more favorable over a 1º!! They got 14 because technically, a chlorine atom can attach everywhere on this structure! Wherever there's a hydrogen, a chlorine can be substituted. Read up on radical reaction and halogen subsitution on alkanes!
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.1
You have highlighted 15 positions; Actually, two of them at bottomleft lead to the same compound. So there are only 14 possibilities. dw:1359014949581:dw
 one year ago

abb0tBest ResponseYou've already chosen the best response.1
My bad. Totally missed that. Thanks @VincentLyon.Fr
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
ch3 here 3 hydogen r present so we count 3 time i.e we can place chlorine 3 time dw:1359169049356:dw
 one year ago

abb0tBest ResponseYou've already chosen the best response.1
I don't understand your question.
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
the three places are equivalent
 one year ago
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