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prove that the length of the perpendicular from the origin to the straight line joining the two points having coordinates ( a cos alpha, a sin alpha) and (a cos beta, a sin beta) is
a cos { ( alpha + beta)/2}.
 one year ago
 one year ago
prove that the length of the perpendicular from the origin to the straight line joining the two points having coordinates ( a cos alpha, a sin alpha) and (a cos beta, a sin beta) is a cos { ( alpha + beta)/2}.
 one year ago
 one year ago

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sauravshakyaBest ResponseYou've already chosen the best response.1
Equation of line passing through ( a cos alpha, a sin alpha) and (a cos beta, a sin beta) is ya sin alpha = (a sinbeta a sinalpha)/( a cosbetaa cosalpha) *(xa cosalpha) ya sinalpha= (sinbeta sinalpha)(xa cosalpha)/(cosbeta cosalpha) y(cosbeta cosaplha) asinalpha (cosbeta cosalpha) = (sinbetasinalpha)(xacosalpha) y(cos betacosalpha) =(sinbetasinalpha)x acosalpha sinbeta+asinalpha cosbeta (sinbetasinalpha)x +(cosalpha cosbeta)y +a(sinalpha cosbeta sinbeta cosalpha)
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
dw:1359027554983:dwNow, Distance between a line Ax+By+C=0 and point (x1,y1) is
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
Try to use that formula
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
A=sinbeta sinalpha B=cosalpha cosbeta C=a(sinalpha cosbeta sinbeta cosalpha) x1=0 y1=0
 one year ago

msinghBest ResponseYou've already chosen the best response.0
at the end, i got a(sinalphacosbetasinbetacosalpha)/√[2+2cos(alpha+beta)]
 one year ago

msinghBest ResponseYou've already chosen the best response.0
asin(alphabeta)/√[2+2cos(alpha+beta)]
 one year ago
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