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msingh
Group Title
prove that the length of the perpendicular from the origin to the straight line joining the two points having coordinates ( a cos alpha, a sin alpha) and (a cos beta, a sin beta) is
a cos { ( alpha + beta)/2}.
 one year ago
 one year ago
msingh Group Title
prove that the length of the perpendicular from the origin to the straight line joining the two points having coordinates ( a cos alpha, a sin alpha) and (a cos beta, a sin beta) is a cos { ( alpha + beta)/2}.
 one year ago
 one year ago

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sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Equation of line passing through ( a cos alpha, a sin alpha) and (a cos beta, a sin beta) is ya sin alpha = (a sinbeta a sinalpha)/( a cosbetaa cosalpha) *(xa cosalpha) ya sinalpha= (sinbeta sinalpha)(xa cosalpha)/(cosbeta cosalpha) y(cosbeta cosaplha) asinalpha (cosbeta cosalpha) = (sinbetasinalpha)(xacosalpha) y(cos betacosalpha) =(sinbetasinalpha)x acosalpha sinbeta+asinalpha cosbeta (sinbetasinalpha)x +(cosalpha cosbeta)y +a(sinalpha cosbeta sinbeta cosalpha)
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
dw:1359027554983:dwNow, Distance between a line Ax+By+C=0 and point (x1,y1) is
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Try to use that formula
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
A=sinbeta sinalpha B=cosalpha cosbeta C=a(sinalpha cosbeta sinbeta cosalpha) x1=0 y1=0
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
at the end, i got a(sinalphacosbetasinbetacosalpha)/√[2+2cos(alpha+beta)]
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
asin(alphabeta)/√[2+2cos(alpha+beta)]
 one year ago
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