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Could you draw the equation please?

$$sin x (9-3)=2/5$$

Is it meant to be this:
\[6\sin(x)=\frac{ 2 }{ 5 }\]

\[\sin \alpha \left( 9-3 \right)=\frac{ 2 }{ 5 }\]

Yes? you are right, but i can't do next step. Arcsin and so on

|dw:1359032768414:dw|

Help please

|dw:1359029896222:dw|

Now, use your calculatoor to evaluate it

Thank you*

welcome