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babyjay

  • one year ago

Can someone help with this question? A candle in the shape of a circular cone has a base of radius r and height of h that is the same length as the radius. Which expresses the ratio of the volume of the candle to its surface area (including the base) for cone v=1/3 pi r^2 and sa= pi r^2 + pi r sqrt r^2+h^2

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  1. sauravshakya
    • one year ago
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    Volume of a cone =1/3 pi r^3 Surface Area of cone = (pi *r*l +pi r^2)

  2. sauravshakya
    • one year ago
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    |dw:1359031569864:dw|

  3. sauravshakya
    • one year ago
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    |dw:1359031666077:dw|

  4. sauravshakya
    • one year ago
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    Volume/Surface AREA = {1/3 pi r^3}/{pi*r^2 +pi*r*l}

  5. sauravshakya
    • one year ago
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    |dw:1359031836785:dw|

  6. sauravshakya
    • one year ago
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    |dw:1359032554268:dw|

  7. sauravshakya
    • one year ago
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    I guess the last option should be r/(3+3 sqrt2)

  8. babyjay
    • one year ago
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    orry makes no sense to me do you mean r/3+sqrt2

  9. sauravshakya
    • one year ago
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    |dw:1359032909108:dw|

  10. sauravshakya
    • one year ago
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    Just simplify it

  11. babyjay
    • one year ago
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    got it think

  12. Whiterabbit541
    • one year ago
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    The Radius. Which expresses the ratio of the volume of the candle to its surface area (including the base)? For a cone, V = 1/3 pi r^2 and SA = Pi r^2 √r^2 + h^2 A) 3r - √h^2 +r^2/8r - h (0 points) B) r(1 - √2) / - 3 (1 point) C) rh/3r + √h^2 + r^2 (0 points) D) r/3 + √2 (0 points) 1/1 point

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