anonymous
  • anonymous
Can someone help with this question? A candle in the shape of a circular cone has a base of radius r and height of h that is the same length as the radius. Which expresses the ratio of the volume of the candle to its surface area (including the base) for cone v=1/3 pi r^2 and sa= pi r^2 + pi r sqrt r^2+h^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Volume of a cone =1/3 pi r^3 Surface Area of cone = (pi *r*l +pi r^2)
anonymous
  • anonymous
|dw:1359031569864:dw|
anonymous
  • anonymous
|dw:1359031666077:dw|

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anonymous
  • anonymous
Volume/Surface AREA = {1/3 pi r^3}/{pi*r^2 +pi*r*l}
anonymous
  • anonymous
|dw:1359031836785:dw|
anonymous
  • anonymous
|dw:1359032554268:dw|
anonymous
  • anonymous
I guess the last option should be r/(3+3 sqrt2)
anonymous
  • anonymous
orry makes no sense to me do you mean r/3+sqrt2
anonymous
  • anonymous
|dw:1359032909108:dw|
anonymous
  • anonymous
Just simplify it
anonymous
  • anonymous
got it think
anonymous
  • anonymous
The Radius. Which expresses the ratio of the volume of the candle to its surface area (including the base)? For a cone, V = 1/3 pi r^2 and SA = Pi r^2 √r^2 + h^2 A) 3r - √h^2 +r^2/8r - h (0 points) B) r(1 - √2) / - 3 (1 point) C) rh/3r + √h^2 + r^2 (0 points) D) r/3 + √2 (0 points) 1/1 point

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