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babyjay
 3 years ago
Can someone help with this question?
A candle in the shape of a circular cone has a base of radius r and height of h that is the same length as the radius. Which expresses the ratio of the volume of the candle to its surface area (including the base) for cone v=1/3 pi r^2 and sa= pi r^2 + pi r sqrt r^2+h^2
babyjay
 3 years ago
Can someone help with this question? A candle in the shape of a circular cone has a base of radius r and height of h that is the same length as the radius. Which expresses the ratio of the volume of the candle to its surface area (including the base) for cone v=1/3 pi r^2 and sa= pi r^2 + pi r sqrt r^2+h^2

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sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.1Volume of a cone =1/3 pi r^3 Surface Area of cone = (pi *r*l +pi r^2)

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1359031569864:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1359031666077:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.1Volume/Surface AREA = {1/3 pi r^3}/{pi*r^2 +pi*r*l}

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1359031836785:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1359032554268:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.1I guess the last option should be r/(3+3 sqrt2)

babyjay
 3 years ago
Best ResponseYou've already chosen the best response.1orry makes no sense to me do you mean r/3+sqrt2

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1359032909108:dw

Whiterabbit541
 2 years ago
Best ResponseYou've already chosen the best response.0The Radius. Which expresses the ratio of the volume of the candle to its surface area (including the base)? For a cone, V = 1/3 pi r^2 and SA = Pi r^2 √r^2 + h^2 A) 3r  √h^2 +r^2/8r  h (0 points) B) r(1  √2) /  3 (1 point) C) rh/3r + √h^2 + r^2 (0 points) D) r/3 + √2 (0 points) 1/1 point
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