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Brooke_army Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits_{}^{} \cos(10x)dx\] u=10x
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
you dont need IBP
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
\[\int\limits cosaxdx =\frac{1}{a} sinax+c\]
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
just use the basic formula : int (cosAx) dx = 1/A * sinAx + c
 one year ago

Brooke_army Group TitleBest ResponseYou've already chosen the best response.0
I don't understand the basic formula
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
@Brooke_army "parts" is something else that you may not have seen yet. this type of integration is usually called "u  substitution"
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
if you didn't have the \(10x\) you would have \[\int cos(x)dx=\sin(x)\] because \[\frac{d}{dx}[\sin(x)]=\cos(x)\] but \[\frac{d}{dx}[\sin(10x)]=10\cos(10x)\] by the chain rule therefore, to get what you want, you have to divide by \(10\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
so if you take the derivative of \(\frac{1}{10}\sin(10x)\) you get exactly what you want, namely \(\cos(10x)\)
 one year ago
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