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anonymous
 4 years ago
Find the integral!!!
anonymous
 4 years ago
Find the integral!!!

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{} \frac{ 3 }{ \sqrt[3]{3x5} } dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I really don't have much a clue for this one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now..Use Substitution Method

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and I take out the 3 on top right?

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2\(u=3x+5\) du/dx=3 \[\int\limits\frac{3}{\sqrt[3]{u}} *\frac{du}{3} =>\int\limits\frac{1}{\sqrt[3]{u}} du=>\int\limits\frac{1}{u^{1/3}} du\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0du / dx = 3 du = 3 dx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0perfect! I'll try it again

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0would it be \[\frac{ 3(3x5)^{2/3} }{ 2 } +c\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is this method called integration by substitution method??

sirm3d
 4 years ago
Best ResponseYou've already chosen the best response.0you can also try \[y=\sqrt[3]{3x5}\Rightarrow y^3=3x5\\3y^2\;\mathrm dy =3\;\mathrm dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yup.....also an other way is by doing direct inverse power......
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