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KatClaireBest ResponseYou've already chosen the best response.0
\[\int\limits_{}^{} \frac{ 3 }{ \sqrt[3]{3x5} } dx\]
 one year ago

KatClaireBest ResponseYou've already chosen the best response.0
I really don't have much a clue for this one
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.2
Now..Use Substitution Method
 one year ago

KatClaireBest ResponseYou've already chosen the best response.0
and I take out the 3 on top right?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
\(u=3x+5\) du/dx=3 \[\int\limits\frac{3}{\sqrt[3]{u}} *\frac{du}{3} =>\int\limits\frac{1}{\sqrt[3]{u}} du=>\int\limits\frac{1}{u^{1/3}} du\]
 one year ago

KatClaireBest ResponseYou've already chosen the best response.0
perfect! I'll try it again
 one year ago

KatClaireBest ResponseYou've already chosen the best response.0
would it be \[\frac{ 3(3x5)^{2/3} }{ 2 } +c\]
 one year ago

Ravi2Best ResponseYou've already chosen the best response.0
is this method called integration by substitution method??
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
you can also try \[y=\sqrt[3]{3x5}\Rightarrow y^3=3x5\\3y^2\;\mathrm dy =3\;\mathrm dx\]
 one year ago

Ravi2Best ResponseYou've already chosen the best response.0
yup.....also an other way is by doing direct inverse power......
 one year ago
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