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DeadShot

  • 3 years ago

Help? Determine the zeros of f(x) = x3 - 3x2 - 16x + 48.

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  1. shubhamsrg
    • 3 years ago
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    take x^2 common from 1st 2 terms take -16 common from last 2 terms

  2. DeadShot
    • 3 years ago
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    so, then it's (x - 3 - x + (-3))?

  3. shubhamsrg
    • 3 years ago
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    eh ? it will be x^2 (x-3) -16(x-3) Following ?

  4. DeadShot
    • 3 years ago
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    oh, I get it. But what do I do next?

  5. shubhamsrg
    • 3 years ago
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    take (x-3) common out I'd say ?

  6. DeadShot
    • 3 years ago
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    so then, it'll be (x^2 - 16) ?

  7. shubhamsrg
    • 3 years ago
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    actually it'll be (x^2-16)(x-3)

  8. shubhamsrg
    • 3 years ago
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    Hope you can find the zeroes now.

  9. DeadShot
    • 3 years ago
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    ok, thanks!

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