## marcoduuuh 2 years ago What is the length of side x in the triangle below? A. 18.46 B. 28.48 C. 24.63 D. 21.21 E. 19.65 F. 24.04 (Picture below.)

1. marcoduuuh

2. jazy

SOH-CAH-TOA |dw:1359045969808:dw| You have the adjacent and hypotenuse, so we use cosine. cos = adj/hyp cos45 = 17/x

3. ashishthomas7

the given triangle can be drawn as |dw:1359046012943:dw|

4. ashishthomas7

use eqn which @jazy told

5. tayluvsya

6. jazy

cos(45) = 17/x 0.707 = 17/x Multiply both sides by x. 0.707x = 17 Divide both sides by 0.707. x = 17 / 0.707 What do you get?

7. marcoduuuh

1377.69?

8. marcoduuuh

@tayluvsya what?

9. jazy

By the way, this calculator helps a lot with these kind of equations. My teacher recommended it. (: http://web2.0calc.com/

10. jazy

Marco divide 17 by 0.707.

11. tayluvsya

12. marcoduuuh

Oh cool! Thanks @jazy. And I got 24.05?

13. jazy

Yeah you're right. (: Actually when I did cos(45) it was actually 0.7071. So 17 divided by 0.7071, rounded would be 24.04.

14. marcoduuuh

Ups, I rounded it wrong :p

15. jazy

No you got it right, I rounded too early in the process, sorryyyy! (: