marcoduuuh
What is the length of side x in the triangle below?
A. 18.46
B. 28.48
C. 24.63
D. 21.21
E. 19.65
F. 24.04
(Picture below.)



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marcoduuuh
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jazy
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SOHCAHTOA
dw:1359045969808:dw
You have the adjacent and hypotenuse, so we use cosine.
cos = adj/hyp
cos45 = 17/x

ashishthomas7
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the given triangle can be drawn as dw:1359046012943:dw

ashishthomas7
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use eqn which @jazy told

tayluvsya
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your post is blinking y

jazy
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cos(45) = 17/x
0.707 = 17/x
Multiply both sides by x.
0.707x = 17
Divide both sides by 0.707.
x = 17 / 0.707
What do you get?

marcoduuuh
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1377.69?

marcoduuuh
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@tayluvsya what?

jazy
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By the way, this calculator helps a lot with these kind of equations. My teacher recommended it. (:
http://web2.0calc.com/

jazy
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Marco divide 17 by 0.707.

tayluvsya
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your question was blinking it stopped never mind

marcoduuuh
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Oh cool! Thanks @jazy.
And I got 24.05?

jazy
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Yeah you're right. (:
Actually when I did cos(45) it was actually 0.7071. So 17 divided by 0.7071, rounded would be 24.04.

marcoduuuh
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Ups, I rounded it wrong :p

jazy
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No you got it right, I rounded too early in the process, sorryyyy! (: