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marcoduuuh

  • 3 years ago

What is the length of side x in the triangle below? A. 18.46 B. 28.48 C. 24.63 D. 21.21 E. 19.65 F. 24.04 (Picture below.)

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  1. marcoduuuh
    • 3 years ago
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  2. jazy
    • 3 years ago
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    SOH-CAH-TOA |dw:1359045969808:dw| You have the adjacent and hypotenuse, so we use cosine. cos = adj/hyp cos45 = 17/x

  3. ashishthomas7
    • 3 years ago
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    the given triangle can be drawn as |dw:1359046012943:dw|

  4. ashishthomas7
    • 3 years ago
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    use eqn which @jazy told

  5. tayluvsya
    • 3 years ago
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    your post is blinking y

  6. jazy
    • 3 years ago
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    cos(45) = 17/x 0.707 = 17/x Multiply both sides by x. 0.707x = 17 Divide both sides by 0.707. x = 17 / 0.707 What do you get?

  7. marcoduuuh
    • 3 years ago
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    1377.69?

  8. marcoduuuh
    • 3 years ago
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    @tayluvsya what?

  9. jazy
    • 3 years ago
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    By the way, this calculator helps a lot with these kind of equations. My teacher recommended it. (: http://web2.0calc.com/

  10. jazy
    • 3 years ago
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    Marco divide 17 by 0.707.

  11. tayluvsya
    • 3 years ago
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    your question was blinking it stopped never mind

  12. marcoduuuh
    • 3 years ago
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    Oh cool! Thanks @jazy. And I got 24.05?

  13. jazy
    • 3 years ago
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    Yeah you're right. (: Actually when I did cos(45) it was actually 0.7071. So 17 divided by 0.7071, rounded would be 24.04.

  14. marcoduuuh
    • 3 years ago
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    Ups, I rounded it wrong :p

  15. jazy
    • 3 years ago
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    No you got it right, I rounded too early in the process, sorryyyy! (:

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