Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

In the diagram below, is an altitude of WXY. What is the length of ? If necessary, round your answer to two decimal places. (Picture below.)

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

lulz no picture
1 Attachment
I JUST POSTED IT STEWP3D.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

What are your answer choices? o:
They give me none. ):
Well you can use the Pythagorean Thereom to get side WX, which rounded off is 14.4, and the triangles look proportional to me, but to check: \[\frac{ WZ }{ WX } = \frac{ WX }{ WY}\] \[\frac{ 10 }{ 14.4 } = \frac{ 14.4 }{ WY }\] Then you cross multiply to get WY= 20.74 WY=WZ+YZ Substitute in values: 20.74= 10+YZ Subtract 10 from both sides: YZ= 10.74
WX = 10 sqrt(2) by the Pythagorean Theorem. WY/WX = WX/10 because of similar triangles. WY = [(WX)^2]/10 = 20 WY = WZ + YZ YZ = 10
THANK YOU.
Good luck in all of your studies and thx for the recognition! you're welcome! @marcoduuuh

Not the answer you are looking for?

Search for more explanations.

Ask your own question