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anonymous
 3 years ago
Find the limit or state that it does not exist lim x>0  f(x)
anonymous
 3 years ago
Find the limit or state that it does not exist lim x>0  f(x)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@RadEn can u help me??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@supercrazy92 can u help?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@RadEn umm yea it is telling me what is the limit in lim x>0 f(x) and if there is no limit to state that it doesnt exist

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1hmmm.. actually, the value of f(x) is given like f(x) = 3x, f(x) = x^2, or what ...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea but its not asking for a value its asking for its limit

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@AravindG um can u help?

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1looks it does not exist, because on the graph, the value of f(x) not consist at around x=0^ (for f(0) = 2, f(1)=0, etc...) but im not sure too

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1why Zarkon, thank for confirm :)

Zarkon
 3 years ago
Best ResponseYou've already chosen the best response.2I'm not giving out answers

Zarkon
 3 years ago
Best ResponseYou've already chosen the best response.2I will tell you if you are correct though

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1yup, i see. but i need ur opinion, somethink rule i miss about this

Zarkon
 3 years ago
Best ResponseYou've already chosen the best response.2what is the value of \(f\) getting close to as you let x get close to zero from the left

Zarkon
 3 years ago
Best ResponseYou've already chosen the best response.2just follow along the graph

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1yup, i just remember now.. just follow along the graph :) thank u @Zarkon for ur confirm, and im sorry @onegirl for my bad :(

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its okay thank you all for your help!
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