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anonymous
 3 years ago
Please help me solve? I'm not getting it right...
x^2+2x+9=0
anonymous
 3 years ago
Please help me solve? I'm not getting it right... x^2+2x+9=0

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[x = \frac{ b \pm \sqrt{b ^{2}4ac} }{ 2a }\] This is the quadratic formula... from your question x^2+2x+9=0 a=1, b = 2,c = 9.. now plug in values u will get 2 values of x

lacypennelll
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1359049498036:dw

lacypennelll
 3 years ago
Best ResponseYou've already chosen the best response.1Might want to close this question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I got \[x=1\pm \sqrt{18}\] which does not look right at all...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0My answer choices are: a. \[x=2\pm4i \sqrt{2}\] b. \[x=2\pm2i \sqrt{2}\] c. \[x=1\pm4i \sqrt{2}\] d. \[x=1\pm2i \sqrt{2}\]
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