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P.nut1996

  • 2 years ago

Please help me solve? I'm not getting it right... x^2+2x+9=0

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  1. nubeer
    • 2 years ago
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    \[x = \frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\] This is the quadratic formula... from your question x^2+2x+9=0 a=1, b = 2,c = 9.. now plug in values u will get 2 values of x

  2. lacypennelll
    • 2 years ago
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    |dw:1359049498036:dw|

  3. lacypennelll
    • 2 years ago
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    Might want to close this question

  4. P.nut1996
    • 2 years ago
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    I got \[x=-1\pm \sqrt{-18}\] which does not look right at all...

  5. P.nut1996
    • 2 years ago
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    My answer choices are: a. \[x=-2\pm4i \sqrt{2}\] b. \[x=-2\pm2i \sqrt{2}\] c. \[x=-1\pm4i \sqrt{2}\] d. \[x=-1\pm2i \sqrt{2}\]

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