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Troublemaker
 one year ago
Best ResponseYou've already chosen the best response.0Well what is it?...

vivalakoda
 one year ago
Best ResponseYou've already chosen the best response.03 log 2 x + 1/2 log 2 y – 3 log 2 z = log 2 (x^3√y / z^3).

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2Nothing is impossible.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2Okay, that's an impossible equation indeed. But it has multiple solutions.

vivalakoda
 one year ago
Best ResponseYou've already chosen the best response.0Exaggeration of course, ha

vivalakoda
 one year ago
Best ResponseYou've already chosen the best response.0So it is capable of being solved? I could call it true?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2Yes, it can be solved by using these identities:\[\log_a b + \log _a c = \log_a (bc)\]and\[\log_a b  \log_a c = \log_a (b/c)\]

jiteshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.2\[\log_2x^3+\log_2y^{1/2}\log_2z^3=\log_2(x^3\sqrt{y}/z^3)\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2Two more:\[a\log b = \log b^a\]and\[\log_a b = \log_a c \iff b = c\]

jiteshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.2now i think it's possible now

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2I am very, very lazy and I am very, very serious about that. So I think @jiteshmeghwal9 will continue helping :p

vivalakoda
 one year ago
Best ResponseYou've already chosen the best response.0It asks me if the equation is true, and if so then to explain the properties used. o.o

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2The identities I listed.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2Use them onebyone.

jiteshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.2\(log_2x^3+log_2(y^{1/2})=log_2(x^3\sqrt{y})\) now \(log_2(x^3\sqrt{y})log_2z^3=log_2(x^3\sqrt{y}/z^3)\)

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2That's it, right there. ^

jiteshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.2\[\log_2x^3+\log_2y^{1/2}\log_2z^3=\log_2(x^3\sqrt{y}/z^3)\]since\[\log_2x^3+\log_2(y^{1/2})=\log_2(x^3\sqrt{y})\]\[\log_2(x^3\sqrt{y})\log_2z^3=\log_2(x^3\sqrt{y}/z^3)\]so,\[\log_2(x^3\sqrt{y}/z^3)=\log_2(x^3\sqrt{y}/z^3)\]H.P.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2Brotip: Use Q.E.D. instead of H.P. :)

vivalakoda
 one year ago
Best ResponseYou've already chosen the best response.0I am so confused. Thank you everyone for the help, I'll just do my best to take the identities you both listed and write something about it. Very much appreciated!

jiteshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.2yw :) Best of luck;)

vivalakoda
 one year ago
Best ResponseYou've already chosen the best response.0By properties they mean the logarithmic properties :c I just asked my teacher. So the power property, the product property, and the quotient property? Would any of those fit?

AravindG
 one year ago
Best ResponseYou've already chosen the best response.0Power Property \[\log a^b=b \log a\] Product Property \[\log ab= \log a +\log b \] Quotient property \[\log \dfrac{a}{b}=\log a  \log b\]

jiteshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.2\(blog_ac=log_ac^b\) \(log_ab+log_ac=log_abc\) \(log_ab  log_ac=log_a\dfrac{b}{c}\)

jiteshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.2these are the only properties used in the question

vivalakoda
 one year ago
Best ResponseYou've already chosen the best response.0How do they show that the equation is true, though?

jiteshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.2I have proved this above
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