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Troublemaker
 2 years ago
Best ResponseYou've already chosen the best response.0Well what is it?...

vivalakoda
 2 years ago
Best ResponseYou've already chosen the best response.03 log 2 x + 1/2 log 2 y – 3 log 2 z = log 2 (x^3√y / z^3).

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.2Nothing is impossible.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.2Okay, that's an impossible equation indeed. But it has multiple solutions.

vivalakoda
 2 years ago
Best ResponseYou've already chosen the best response.0Exaggeration of course, ha

vivalakoda
 2 years ago
Best ResponseYou've already chosen the best response.0So it is capable of being solved? I could call it true?

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.2Yes, it can be solved by using these identities:\[\log_a b + \log _a c = \log_a (bc)\]and\[\log_a b  \log_a c = \log_a (b/c)\]

jiteshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.2\[\log_2x^3+\log_2y^{1/2}\log_2z^3=\log_2(x^3\sqrt{y}/z^3)\]

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.2Two more:\[a\log b = \log b^a\]and\[\log_a b = \log_a c \iff b = c\]

jiteshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.2now i think it's possible now

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.2I am very, very lazy and I am very, very serious about that. So I think @jiteshmeghwal9 will continue helping :p

vivalakoda
 2 years ago
Best ResponseYou've already chosen the best response.0It asks me if the equation is true, and if so then to explain the properties used. o.o

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.2The identities I listed.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.2Use them onebyone.

jiteshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.2\(log_2x^3+log_2(y^{1/2})=log_2(x^3\sqrt{y})\) now \(log_2(x^3\sqrt{y})log_2z^3=log_2(x^3\sqrt{y}/z^3)\)

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.2That's it, right there. ^

jiteshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.2\[\log_2x^3+\log_2y^{1/2}\log_2z^3=\log_2(x^3\sqrt{y}/z^3)\]since\[\log_2x^3+\log_2(y^{1/2})=\log_2(x^3\sqrt{y})\]\[\log_2(x^3\sqrt{y})\log_2z^3=\log_2(x^3\sqrt{y}/z^3)\]so,\[\log_2(x^3\sqrt{y}/z^3)=\log_2(x^3\sqrt{y}/z^3)\]H.P.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.2Brotip: Use Q.E.D. instead of H.P. :)

vivalakoda
 2 years ago
Best ResponseYou've already chosen the best response.0I am so confused. Thank you everyone for the help, I'll just do my best to take the identities you both listed and write something about it. Very much appreciated!

jiteshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.2yw :) Best of luck;)

vivalakoda
 2 years ago
Best ResponseYou've already chosen the best response.0By properties they mean the logarithmic properties :c I just asked my teacher. So the power property, the product property, and the quotient property? Would any of those fit?

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.0Power Property \[\log a^b=b \log a\] Product Property \[\log ab= \log a +\log b \] Quotient property \[\log \dfrac{a}{b}=\log a  \log b\]

jiteshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.2\(blog_ac=log_ac^b\) \(log_ab+log_ac=log_abc\) \(log_ab  log_ac=log_a\dfrac{b}{c}\)

jiteshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.2these are the only properties used in the question

vivalakoda
 2 years ago
Best ResponseYou've already chosen the best response.0How do they show that the equation is true, though?

jiteshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.2I have proved this above
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