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TroublemakerBest ResponseYou've already chosen the best response.0
Well what is it?...
 one year ago

vivalakodaBest ResponseYou've already chosen the best response.0
3 log 2 x + 1/2 log 2 y – 3 log 2 z = log 2 (x^3√y / z^3).
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Nothing is impossible.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Okay, that's an impossible equation indeed. But it has multiple solutions.
 one year ago

vivalakodaBest ResponseYou've already chosen the best response.0
Exaggeration of course, ha
 one year ago

vivalakodaBest ResponseYou've already chosen the best response.0
So it is capable of being solved? I could call it true?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Yes, it can be solved by using these identities:\[\log_a b + \log _a c = \log_a (bc)\]and\[\log_a b  \log_a c = \log_a (b/c)\]
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
\[\log_2x^3+\log_2y^{1/2}\log_2z^3=\log_2(x^3\sqrt{y}/z^3)\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Two more:\[a\log b = \log b^a\]and\[\log_a b = \log_a c \iff b = c\]
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
now i think it's possible now
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
I am very, very lazy and I am very, very serious about that. So I think @jiteshmeghwal9 will continue helping :p
 one year ago

vivalakodaBest ResponseYou've already chosen the best response.0
It asks me if the equation is true, and if so then to explain the properties used. o.o
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
The identities I listed.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Use them onebyone.
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
\(log_2x^3+log_2(y^{1/2})=log_2(x^3\sqrt{y})\) now \(log_2(x^3\sqrt{y})log_2z^3=log_2(x^3\sqrt{y}/z^3)\)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
That's it, right there. ^
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
\[\log_2x^3+\log_2y^{1/2}\log_2z^3=\log_2(x^3\sqrt{y}/z^3)\]since\[\log_2x^3+\log_2(y^{1/2})=\log_2(x^3\sqrt{y})\]\[\log_2(x^3\sqrt{y})\log_2z^3=\log_2(x^3\sqrt{y}/z^3)\]so,\[\log_2(x^3\sqrt{y}/z^3)=\log_2(x^3\sqrt{y}/z^3)\]H.P.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Brotip: Use Q.E.D. instead of H.P. :)
 one year ago

vivalakodaBest ResponseYou've already chosen the best response.0
I am so confused. Thank you everyone for the help, I'll just do my best to take the identities you both listed and write something about it. Very much appreciated!
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
yw :) Best of luck;)
 one year ago

vivalakodaBest ResponseYou've already chosen the best response.0
By properties they mean the logarithmic properties :c I just asked my teacher. So the power property, the product property, and the quotient property? Would any of those fit?
 one year ago

AravindGBest ResponseYou've already chosen the best response.0
Power Property \[\log a^b=b \log a\] Product Property \[\log ab= \log a +\log b \] Quotient property \[\log \dfrac{a}{b}=\log a  \log b\]
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
\(blog_ac=log_ac^b\) \(log_ab+log_ac=log_abc\) \(log_ab  log_ac=log_a\dfrac{b}{c}\)
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
these are the only properties used in the question
 one year ago

vivalakodaBest ResponseYou've already chosen the best response.0
How do they show that the equation is true, though?
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.2
I have proved this above
 one year ago
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