1. Torrayani<3

1. If f(x) = 3x + 1 and g(x) = 2x − 4, find f[g(2)]. 25 4 zero 1 2. If f(x) = −x − 1 and g(x) = 4x − 1, find f[g(−2)] −10 −9 −13 8 3. If f(x) = x + 3 and g(x) = −4x − 1, find g[f(4)]. 21 −21 19 −19 4. If f(x) = 4x + 1 and g(x) = −x − 2, find (f + g)(−1). −4<==== 4 −6 −8 5. If f(x) = 2x − 2 and g(x) = 3x − 1, find (f − g)(4). 17 −17 5 −5 6. If f(x) = x − 2 and g(x) = −2x − 1, find (f g)(9) 19 −18 zero −19 7. If f(x) = −2x − 4 and g(x) = x + 4, find ()(−8). −3 3 −1 1 8. If f(x) = x − 4 and g(x) = x − 2, find f[g(−6)]. 9 3 −9 −3 9. If h(x) = 3x − 1 and j(x) = −2x, find h[j(2)]. 11 −11 13 −13<==== 10. If r(x) = 3x − 1 and t(x) = −4x − 1, find (r + t)(7). 9 −9<==== −49 49

2. hba

Please post a single question at a time.

3. Torrayani<3

4. Torrayani<3

@hba

5. hba

Giving direct Answers is not allowed on OS.

6. marvin.cling

1 for the first question

7. marvin.cling

to get that you plug in 0 into g(x) then plug your solution 0 into f(x)

8. marvin.cling

and you get 1

9. Torrayani<3

I didn't say don't explain

10. Torrayani<3

Thank you @marvin.cling

11. marvin.cling

i explained do you want more explanation? \[g(2)=2(2)-4=0, f(g(2))= 3(0)+1=1. How's that for an explanation\]

12. marvin.cling

sorry i meant two not 0

13. Torrayani<3

no just plaese answer my next post