## anonymous 3 years ago What is the equation of the hyperbola with foci at (0, ±10) and vertices at (0, ±8)?

center(0,0)vertical transverse axis a=8 c=10 $c^2-a^2=b^2$ b= ___ (y)² /36 - (x)²/ 64 =1 $\frac{ y^2 }{ b^2 }-\frac{ x^2 }{ c^2 }=1$ (vertices (0,±a)