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there is few ways of working this out. Elimination, Substitution and maybe multiplication

which way do you prefer?

i need my mind refreshed. whichever method works best is the method i choose.

ill use substitution then :P
x = \[x = y - \frac{ 1 }{ 5 }\]
25x + ky = 4

25(y - \[25(y - \frac{ 1 }{ 5 }) + ky = 4\]

\[25y - 5 + ky = 4\]

do you get it now?

howd u get y-(1/5)?

divide everything in the first equation by 5

there is no solution :)

ill use elimination now

times the first equation by -5
-25x - 25y = -5
25x + ky = 4

now add this equation vertically together.
it would give you k=25

haha great :/
u say that now

you know why there is no solution?
if you sub K = 25 it wont work

:(

yes?

because they equal different things

haha no, THANK YOU ! :)

ok i have another one lol
this one wants the k to have an infinite amount of solutions

49x-49y=49
7x+ky=7

the answer is not 1,7,49,1/7, or 1/49.

sorry been bit busy

so do you have an idea where to start?

i would times the 2nd equation by 7

ok...

do you undertand this yet lol?

49x-49y=49
7x+ky=7
49x-49y=49
49x + 7ky = 49

dont know where to go from there

-49y - 7ky = 0
-7y(7 + k) = 0

how do we get the k from that

im bit confused :P
you sure their is more than 1 answer??

its 1 answer

oh u said
this one wants the k to have an infinite amount of solutions

1 K but infinite solutions
we need the K

y(7 + k ) = 0
from this can you find K?
im pretty sure you can :P

hint: you only need to look at this question to get K

ok its -7 lol

im feeling slooow ha

ok i g2g now :)

have fun with your maths

haha see ya.