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needmathhelp7
 2 years ago
What is the value of y in the parallelogram below? if necessary, round your answer to two decimal places
needmathhelp7
 2 years ago
What is the value of y in the parallelogram below? if necessary, round your answer to two decimal places

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needmathhelp7
 2 years ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 @mathstudent55 @Mertsj @skullpatrol @RyanL.

Ahsher97
 2 years ago
Best ResponseYou've already chosen the best response.0...........what grade are you in that you cant answer that?

needmathhelp7
 2 years ago
Best ResponseYou've already chosen the best response.0@Ahsher97 Wow you're nice ______ if you're not gonna help than don't come on here

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Yah wow that's pretty rude... not everyone is learning on the same level as you ash :\

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Since it's a quadrilateral, how many degrees in total do the interior angles add up to? :)

needmathhelp7
 2 years ago
Best ResponseYou've already chosen the best response.0@zepdrix Awh, thanks! yeah, I'm just trying to finish up my math so I can graduate. It's all I have left, I just need a lil help! do they add up to 70 degrees? :)

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1lol no silly! :) In a triangle, the interior angles add to \(180^o\). In a quadrilateral the interior angles add to \(360^o\). Since we have a PARALLELOGRAM, the angles opposite one another will be equal.

Ahsher97
 2 years ago
Best ResponseYou've already chosen the best response.0i didnt post that sorry my friend is over :/

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1If you look at the picture, that means that \(65^o=(2x+3)^o\) because those two angles are opposite one another. Ok ok but let's think a little bit differently, since we don't need \(x\). If that angle is 65, and the angle involving \(x\) is also 65, and we determined that a quadrilateral has 360 degrees total. Hmmmm. So those 2 angles \(65^o+65^o=130^o\) How much does that leave over for the other 2 angles? :D

needmathhelp7
 2 years ago
Best ResponseYou've already chosen the best response.0Oh! So what's the opposite? @Ahsher97 Lol, it's all good :)

Ahsher97
 2 years ago
Best ResponseYou've already chosen the best response.0he shouldn't really talk he had to do summer school all four years of highschool

needmathhelp7
 2 years ago
Best ResponseYou've already chosen the best response.0Lolol awhh poor guy xD well at least you didn't say that! I bet your friend was just kiddin' around anyway :)

needmathhelp7
 2 years ago
Best ResponseYou've already chosen the best response.0@zepdrix is the opposite 65 degrees?

needmathhelp7
 2 years ago
Best ResponseYou've already chosen the best response.0since the left angle is opposite? :)

tyteen4a03
 2 years ago
Best ResponseYou've already chosen the best response.1@Ahsher97 Please be nice to askers, regardless of which grade he/she is in. You have been there at one point. Another way to look at this is by using Interior Angles property (i.e 65+5y =180)

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1359070814837:dwThis upper angle is also 65 since it's opposite the 65 in a parallelogram. How many degrees does that leave us with for the OTHER two angles if these two are each 65, and a quadrilateral has 360 degrees total? :D

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Am I confusing you gal? :c

needmathhelp7
 2 years ago
Best ResponseYou've already chosen the best response.0no not at all! @zepdrix ! I think I got it! but idk :) so I did: 18065= 115 and divided by 5

tyteen4a03
 2 years ago
Best ResponseYou've already chosen the best response.1@zepdrix For these type of questions I wouldn't recommend using the sum of interior angles property, because extra steps are required. Instead use the interior angle property.

needmathhelp7
 2 years ago
Best ResponseYou've already chosen the best response.0@tyteen4a03 You're great!! Could I do it like that? :)

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Yah I don't do a lot of geometry c: So I'm always at a loss as to how I should approach these problems :3

needmathhelp7
 2 years ago
Best ResponseYou've already chosen the best response.0Awesome! thank you guys so much!! New question coming up :D
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